0

当我尝试使用 API 并模拟不同的位置时，我收到了 REQUEST_DENIED 错误。API 文档中的示例参数有效，但是当我使用不同的经纬度坐标时，它会以 REQUEST_DENIED 的形式反弹。大约一周前它还在工作。请问我能做什么？

php中的代码：

......////

                  $url = "https://maps.googleapis.com/maps/api/place/search/json?location=".$latitude.",
                  ".$longitude."&radius=100&sensor=false&key=".$key."";

                   // Open the Curl session
                      $session = curl_init($url);

                      // If it's a POST, put the POST data in the body
                      //if ($_POST['path']) {
                          $postvars = '';
                          while ($element = current($_GET)) {
                              $postvars .= urlencode(key($_GET)).'='.urlencode($element).'&';
                              next($_GET);
                          }
                          curl_setopt ($session, CURLOPT_POST, true);
                          curl_setopt ($session, CURLOPT_POSTFIELDS, $postvars);
                      //}

                      // Don't return HTTP headers. Do return the contents of the call
                      curl_setopt($session, CURLOPT_HEADER, false);
                      curl_setopt($session, CURLOPT_RETURNTRANSFER, true);
                      curl_setopt($session, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); 
                      //curl_setopt($session, CURLOPT_USERPWD, $username.':'.urldecode($password));

                      // Make the call
                      $json = curl_exec($session);
4

0 回答 0