我花了很多时间尝试"yIH7EYW0e4HuxkHApkG7xQ=="
在 PHP 服务器端解密一个加密字符串 (),但没有成功。该字符串在 iOS 平台上进行了加密,并使用 base64 格式编码为文本。
无论如何,有人可以纠正我在 PHP 方面的错误(我在这方面有点弱)吗?我知道这种方法不是很安全。我只需要一个临时解决方案,直到我可以使用 openssl 研究更好的方法。
PHP:
$str_encrypted = "yIH7EYW0e4HuxkHApkG7xQ=="; // base64encoded
$mykey = "my password";
$decrypted = decrypt_data($str_encrypted =, $mykey);
function decrypt_data($str_encrypted =, $mykey)
{
$iv_size = mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_ECB);
$iv = mcrypt_create_iv($iv_size, MCRYPT_RAND);
$decrypted_text = mcrypt_decrypt(MCRYPT_RIJNDAEL_128, $encryptionkey, $text, MCRYPT_MODE_ECB, $iv);
return $decrypted_text;
}
IOS:
- (NSString *)AES128EncryptWithKey:(NSString *)key
{
NSData *plainData = [self dataUsingEncoding:NSUTF8StringEncoding];
NSData *encryptedData = [plainData AES128EncryptWithKey:key];
NSString *encryptedString = [encryptedData base64Encoding];
return encryptedString;
}
IOS:
- (NSString *)base64Encoding
{
const unsigned char *bytes = [self bytes];
NSMutableString *result = [NSMutableString stringWithCapacity:self.length];
unsigned long ixtext = 0;
unsigned long lentext = self.length;
long ctremaining = 0;
unsigned char inbuf[3], outbuf[4];
unsigned short i = 0;
unsigned short charsonline = 0, ctcopy = 0;
unsigned long ix = 0;
while( YES )
{
ctremaining = lentext - ixtext;
if( ctremaining <= 0 ) break;
for( i = 0; i < 3; i++ )
{
ix = ixtext + i;
if( ix < lentext ) inbuf[i] = bytes[ix];
else inbuf [i] = 0;
}
outbuf [0] = (inbuf [0] & 0xFC) >> 2;
outbuf [1] = ((inbuf [0] & 0x03) << 4) | ((inbuf [1] & 0xF0) >> 4);
outbuf [2] = ((inbuf [1] & 0x0F) << 2) | ((inbuf [2] & 0xC0) >> 6);
outbuf [3] = inbuf [2] & 0x3F;
ctcopy = 4;
switch( ctremaining )
{
case 1:
ctcopy = 2;
break;
case 2:
ctcopy = 3;
break;
}
for( i = 0; i < ctcopy; i++ )
[result appendFormat:@"%c", encodingTable[outbuf[i]]];
for( i = ctcopy; i < 4; i++ )
[result appendString:@"="];
ixtext += 3;
charsonline += 4;
}
return [NSString stringWithString:result];
}