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我正在尝试使用 DrawingAreas，但事情并没有按我预期的方式工作。

#include <Xm/Xm.h>
#include <Xm/DrawingA.h>

main(int argc, char *argv[])
{
  Widget shell, workArea, box1;
  XtAppContext app;
  shell = XtVaAppInitialize(&app, "gp", NULL, 0, &argc, argv, NULL, XmNwidth, 500, XmNheight, 500, NULL);
  XtRealizeWidget(shell);

  workArea = XtCreateWidget("wa",xmDrawingAreaWidgetClass, shell, NULL, 0);
  XtVaSetValues(workArea, XmNbackground, 30000, NULL);

  box1 = XtCreateWidget("b1", xmDrawingAreaWidgetClass, workArea, NULL, 0);
  XtVaSetValues(box1, XmNx, 0, XmNy, 0, XmNwidth, 400, XmNheight, 400, NULL);

  XtManageChild(workArea);
  XtManageChild(box1);
  //XtAppMainLoop(app);
  XEvent event;
  Dimension x,y,w,h;
  while(1)
  {
    XtAppNextEvent(app, &event);
    if (event.type == EnterNotify)
    {
      XtVaGetValues(box1, XmNx, &x, XmNy, &y, XmNwidth, &w, XmNheight, &h, NULL);
      printf("(x,y,w,h) == (%d,%d,%d,%d)\n", x, y, w, h);
    }
    if (event.type == LeaveNotify)
    {
      XtVaSetValues(box1, XmNx, 0, XmNy, 0, XmNwidth, 400, XmNheight, 400, NULL);
      printf("tried to set (x,y,w,h) = (0,0,400,400)\n");
    }
    XtDispatchEvent(&event);
  }
}

当我进入窗口并用指针离开窗口时，我得到输出：

(x,y,w,h) == (10,10,400,400)
(x,y,w,h) == (10,10,400,400)
tried to set (x,y,w,h) = (0,0,400,400)
tried to set (x,y,w,h) = (0,0,400,400)
(x,y,w,h) == (10,10,400,400)
(x,y,w,h) == (10,10,400,400)
tried to set (x,y,w,h) = (0,0,400,400)
tried to set (x,y,w,h) = (0,0,400,400)

为什么 XtVaSetValues 不将 box1 设置为 (X,Y) = (0,0)？如何在窗口内的 (0,0) 处放置绘图区域？

我想出了答案，但没有提供它的声誉：

XtManageChild(box1);
XtUnmanageChild(box1);
XtVaSetValues(box1, XmNx, 0, XmNy, 0, XmNwidth, 400, XmNheight, 400, NULL);
XtMapWidget(box1);
4

1 回答 1

1

看起来对 XtManageChild() 的调用正在调用父级的 change_managed 过程：

xtmanpage

为了将 (x,y) 设置为 (0,0)，我必须确保小部件不受管理：

XtManageChild(box1); // must be called once
XtUnmanageChild(box1); // unmanage to allow (0,0)
XtVaSetValues(box1, NmNx, 0, XmNy, 0, XmNwidth, 400, XmNheight, 400, NULL);
XtMapWidget(box1); // show the widget
于 2012-09-28T16:43:41.833 回答