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我正在尝试将图像从我的 android 应用程序共享到 instagram 应用程序…………我无法上传图像…………

@SuppressWarnings("unchecked")
public Map<String, String> doUpload() {
Log.i(TAG, "Upload");
Long timeInMilliseconds = System.currentTimeMillis()/1000;
String timeInSeconds = timeInMilliseconds.toString();
MultipartEntity multipartEntity = new     
MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
Map returnMap = new HashMap<String, String>();
// check for cookies
/*  if( httpClient.getCookieStore() == null ) {
 returnMap.put("result", "Not logged in");
        return returnMap;
    }*/

    try {
        // create multipart data
         System.out.println("image path name : "+processedImageUri.getPath());
         System.out.println("image file path : "+ImgFilePath);
        File imageFile = new File(ImgFilePath);//processedImageUri.getPath());
        FileBody partFile = new FileBody(imageFile);
        StringBody partTime = new StringBody(timeInSeconds);

        multipartEntity.addPart("photo", partFile );
        multipartEntity.addPart("device_timestamp", partTime);
    } catch ( Exception e ) {
        Log.e(TAG,"Error creating mulitpart form: " + e.toString());
        returnMap.put("result", "Error creating mulitpart form: " + e.toString());
        return returnMap;
    }

    // upload
    try {
        System.out.println("111111111111111111");
        System.out.println("multipart entity value : "+multipartEntity.toString());
        HttpPost httpPost = new HttpPost(Utils.UPLOAD_URL);
        httpPost.setEntity(multipartEntity);
        System.out.println("http post vlaue : "+httpPost.toString());
        System.out.println("http client value : "+httpClient.toString());
        HttpResponse httpResponse = httpClient.execute(httpPost);
        System.out.println("Http response value : "+httpResponse.toString());
        HttpEntity httpEntity = httpResponse.getEntity();
        Log.i(TAG, "Upload status: " + httpResponse.getStatusLine());
        System.out.println("staus entity value : "+httpResponse.getStatusLine().toString());
        System.out.println("http status : "+HttpStatus.SC_OK);

        // test result code
        if( httpResponse.getStatusLine().getStatusCode() != HttpStatus.SC_OK ) {
            Log.e(TAG, "Login HTTP status fail: " + httpResponse.getStatusLine().getStatusCode());
            returnMap.put("result", "HTTP status error: " + httpResponse.getStatusLine().getStatusCode() );
            return returnMap;
        }

        // test json response
        // should look like
        /*
        {"status": "ok"}
        */
        if( httpEntity != null ) {
            BufferedReader reader = new BufferedReader(new InputStreamReader(httpEntity.getContent(), "UTF-8"));
            String json = reader.readLine();
            System.out.println("Entity value : "+json);
            JSONTokener jsonTokener = new JSONTokener(json);
            JSONObject jsonObject = new JSONObject(jsonTokener);
            Log.i(TAG,"JSON: " + jsonObject.toString());

            String loginStatus = jsonObject.getString("status");

            if( !loginStatus.equals("ok") ) {
                Log.e(TAG, "JSON status not ok: " + jsonObject.getString("status"));
                returnMap.put("result", "JSON status not ok: " + jsonObject.getString("status") );
                return returnMap;
            }
        }
    } catch( Exception e ) {
        Log.e(TAG, "HttpPost exception: " + e.toString());
        returnMap.put("result", "HttpPost exception: " + e.toString());
        return returnMap;
    }

    // configure / comment
    try {
        HttpPost httpPost = new HttpPost(Utils.CONFIGURE_URL);
        String partComment = txtCaption.getText().toString();
        List<NameValuePair> postParams = new ArrayList<NameValuePair>();
        postParams.add(new BasicNameValuePair("device_timestamp", timeInSeconds));
        postParams.add(new BasicNameValuePair("caption", partComment));
        httpPost.setEntity(new UrlEncodedFormEntity(postParams, HTTP.UTF_8));
        System.out.println("http client value : "+httpClient.toString());
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();

        // test result code
        if( httpResponse.getStatusLine().getStatusCode() != HttpStatus.SC_OK ) {
            Log.e(TAG, "Upload comment fail: " + httpResponse.getStatusLine().getStatusCode());
            returnMap.put("result", "Upload comment fail: " + httpResponse.getStatusLine().getStatusCode() );
            return returnMap;
        }

        returnMap.put("result", "ok");
        return returnMap;
    } catch( Exception e ) {
        Log.e(TAG, "HttpPost comment error: " + e.toString());
        returnMap.put("result", "HttpPost comment error: " + e.toString());
        return returnMap;
    }

以上是我用来上传图片的代码，网址是 UPLOAD_URL = "http://instagr.am/api/v1/media/upload/" ...... .请谁能帮我把图片上传到instagram.......提前谢谢

4

1 回答 1

4

Instagram API 尚不支持上传。

来自 Instagram API 文档：

目前，无法通过 API 上传。我们有意识地选择不添加它，原因如下：

Instagram 是关于你在旅途中的生活——我们希望鼓励从应用程序中拍摄照片。但是，将来我们可能会根据具体情况授予对单个应用程序的白名单访问权限。我们要打击垃圾邮件和低质量的照片。一旦我们允许从其他来源上传，就很难控制进入 Instagram 生态系统的内容。尽管如此，我们正在努力确保用户在我们的平台上获得一致且高质量的体验。

于 2012-09-21T15:45:20.047 回答