14

我以编程方式从通讯簿中检索电子邮件地址的方法似乎不再适用于 iOS 6 设备。它在 iOS 5 中工作，奇怪的是，仍然在 iOS 6 模拟器中工作。是否有一种以编程方式从用户通讯录中检索联系人的新方法？

ABAddressBookRef addressBook = ABAddressBookCreate();
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex nPeople = ABAddressBookGetPersonCount(addressBook);

self.contacts = [[NSMutableArray alloc] init];

int contactIndex = 0;
for (int i = 0; i < nPeople; i++) {
    // Get the next address book record.
    ABRecordRef record = CFArrayGetValueAtIndex(allPeople, i);        

    // Get array of email addresses from address book record.
    ABMultiValueRef emailMultiValue = ABRecordCopyValue(record, kABPersonEmailProperty);
    NSArray *emailArray = (__bridge_transfer NSArray *)ABMultiValueCopyArrayOfAllValues(emailMultiValue);

    [self.contacts addObject:emailArray];
}

为了澄清，上面没有崩溃，它只是不返回任何结果。ABAddressBookCopyArrayOfAllPeople 为空。谢谢！

4

4 回答 4

52

我创建了一个辅助类 ，AddressBookHelper来处理向后兼容性。以下是胆量：

-(BOOL)isABAddressBookCreateWithOptionsAvailable {
    return &ABAddressBookCreateWithOptions != NULL;
}

-(void)loadContacts {
    ABAddressBookRef addressBook;
    if ([self isABAddressBookCreateWithOptionsAvailable]) {
        CFErrorRef error = nil;
        addressBook = ABAddressBookCreateWithOptions(NULL,&error);
        ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
            // callback can occur in background, address book must be accessed on thread it was created on
            dispatch_async(dispatch_get_main_queue(), ^{
                if (error) {
                    [self.delegate addressBookHelperError:self];
                } else if (!granted) {
                    [self.delegate addressBookHelperDeniedAcess:self];
                } else {
                    // access granted
                    AddressBookUpdated(addressBook, nil, self);
                    CFRelease(addressBook);
                }
            });
        });
    } else {
        // iOS 4/5
        addressBook = ABAddressBookCreate();
        AddressBookUpdated(addressBook, NULL, self);
        CFRelease(addressBook);
    }
}

void AddressBookUpdated(ABAddressBookRef addressBook, CFDictionaryRef info, void *context) {
    AddressBookHelper *helper = (AddressBookHelper *)context;
    ABAddressBookRevert(addressBook);
    CFArrayRef people = ABAddressBookCopyArrayOfAllPeople(addressBook);

    // process the contacts to return
    NSArray *contacts = ...    

    [[helper delegate] addressBookHelper:helper finishedLoading:contacts];
};
于 2012-09-21T15:52:23.720 回答
12

可能与新的隐私控制有关——从 iOS 6 开始，在设备上，未经用户许可，应用无法访问用户的联系人。从文档中：

在 iOS 6.0 及更高版本上，如果调用者无权访问通讯簿数据库：

• 对于链接到iOS 6.0 及更高版本的应用程序，此函数返回NULL。

• 对于与早期版本的iOS 链接的应用程序，此函数返回一个空的只读数据库。

如果您没有看到权限警报出现（“SomeApp 想要访问您的联系人”），那么直接地址簿 API 可能只是假设他们没有访问权限并默默地失败；您可能必须显示 AddressBookUI 框架中的某些内容才能触发它。

于 2012-09-20T17:12:21.293 回答
12

试试这个：必须先授予对地址簿的访问权限，然后才能以编程方式访问它。这就是我最终要做的。

  #import <AddressBookUI/AddressBookUI.h>

  // Request authorization to Address Book
  ABAddressBookRef addressBookRef = ABAddressBookCreateWithOptions(NULL, NULL);

  if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusNotDetermined) {
    ABAddressBookRequestAccessWithCompletion(addressBookRef, ^(bool granted, CFErrorRef error) {
      // First time access has been granted, add the contact
      [self _addContactToAddressBook];
    });
  }
  else if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusAuthorized) {
    // The user has previously given access, add the contact
    [self _addContactToAddressBook];
  }
  else {
    // The user has previously denied access
    // Send an alert telling user to change privacy setting in settings app
  }
于 2013-01-10T11:52:55.747 回答
0

可能与新的隐私控制有关，从 iOS 6 开始，设备上的应用程序无法在未经用户许可的情况下访问用户的联系人。

代码：

-(void)addressBookValidation
{



NSUserDefaults *prefs=[NSUserDefaults standardUserDefaults];
ABAddressBookRef addressbook = ABAddressBookCreate();
__block BOOL accessGranted = NO;

if (ABAddressBookRequestAccessWithCompletion != NULL)
{
    if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusNotDetermined)
    {
        dispatch_semaphore_t sema = dispatch_semaphore_create(0);
        ABAddressBookRequestAccessWithCompletion(addressbook, ^(bool granted, CFErrorRef error)
                                                 {
                                                     accessGranted = granted;
                                                     dispatch_semaphore_signal(sema);
                                                 });
        dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
        dispatch_release(sema);
    }
    else if(ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusAuthorized)
    {
        accessGranted = YES;
    }
    else if (ABAddressBookGetAuthorizationStatus()==kABAuthorizationStatusDenied)
    {
        accessGranted = NO;
    }
    else if (ABAddressBookGetAuthorizationStatus()==kABAuthorizationStatusRestricted){
        accessGranted = NO;
    }
    else
    {
        accessGranted = YES;
    }


}
else
{
    accessGranted = YES;
}
[prefs setBool:accessGranted forKey:@"addressBook"];

NSLog(@"[prefs boolForKey:@'addressBook']--->%d",[prefs boolForKey:@"addressBook"]);
[prefs synchronize];
CFRelease(addressbook);
}
于 2013-06-28T12:35:13.113 回答