2

我有下表：

mysql> SELECT *  FROM  `bright_promotion_earnings`;
+----+----------+------------+----------+-------+
| id | promoter | generation | turnover | payed |
+----+----------+------------+----------+-------+
|  1 |        4 |          1 |       10 |     0 | 
|  3 |        4 |          5 |      100 |     0 | 
|  4 |        4 |          3 |    10000 |     1 | 
|  5 |        4 |          3 |      200 |     0 | 
+----+----------+------------+----------+-------+
4 rows in set (0.00 sec)

有一个唯一的密钥（发起人、世代、付费）：

+---------------------------+------------+------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table                     | Non_unique | Key_name   | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+---------------------------+------------+------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| bright_promotion_earnings |          0 | promoter_2 |            1 | promoter    | A         |           2 |     NULL | NULL   | YES  | BTREE      |         | 
| bright_promotion_earnings |          0 | promoter_2 |            2 | generation  | A         |           4 |     NULL | NULL   |      | BTREE      |         | 
| bright_promotion_earnings |          0 | promoter_2 |            3 | payed       | A         |           4 |     NULL | NULL   |      | BTREE      |         | 
+---------------------------+------------+------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
3 rows in set (0.00 sec)

现在，我想通过使用paid=1 更新相同的条目（如果存在），将发起人的每一笔收入标记为已支付。

因此，如果我想将发起人 4 的收入标记为已支付，表格应如下所示：

+----+----------+------------+----------+-------+
| id | promoter | generation | turnover | payed |
+----+----------+------------+----------+-------+
|  4 |        4 |          3 |    10200 |     1 | 
|  6 |        4 |          5 |      100 |     1 | 
|  7 |        4 |          1 |       10 |     1 | 
+----+----------+------------+----------+-------+
3 rows in set (0.00 sec)

这是我目前的方法（没有 DELETE 这是微不足道的）：

INSERT INTO 
    bright_promotion_earnings
    (
        promoter,
        generation,
        turnover,
        payed
    )
SELECT 
    commission.promoter,
    commission.generation,
    commission.turnover as turnover2,
    '1' as payed
FROM  
    bright_promotion_earnings as commission
WHERE  
    promoter=4
    AND payed=0
ON DUPLICATE KEY UPDATE turnover=turnover+turnover2;

但是mysql一直告诉我营业额是模棱两可的：

#1052 - Column 'turnover' in field list is ambiguous

有没有人有提示，因为我不能为我插入的表加上别名。

如何为要插入的表命名，以便 mysql 可以识别该列？

提前致谢。

4

1 回答 1

4

您在两个表中都有一个营业额字段，因此 mysql 无法确定您在最后一行的意思。

于 2009-08-09T11:02:12.580 回答