1

我需要获取一个查询，该查询将显示具有相同银行详细信息的人员的详细信息，这些信息已被错误捕获。

然后，我需要显示这些人的正确详细信息和错误详细信息。例如：

1stName 1stAccNo 1stItemSold 2ndName 2ndAccNo 2ndItemSold
阿尔伯特 2231432 项目 1 约翰 2231432 项目 3
罗伯特 6321009 项目 11 彼得 6321009 项目 3

Name 和 AccNo 在一个表上，而 ItemSold 在另一个表上。

我有以下查询：

select p1.Name As 1stName, p1.AccNo AS 1stAccNo, I.ItemSold AS 1stItemSold, p2.Name AS 2ndName, p2.AccNo AS 2ndAccNo, I.ItemSold As 2ndItemSold
FROM Persons p1 JOIN Persons p2 ON p1.AccNo = p2.AccNo 
INNER JOIN Items I on p.ItemID = I.ItemID

问题是 2nd ItemSold 不正确，因为它与 1stItemSold 相同。我该怎么做才能更改我的查询，以便获得正确的结果？

4

2 回答 2

1

您应该将 Items 作为第二个表加入。此外，如果您需要不同的人，则必须包括where p1.id<>p2.id其中 ID 是 PERSONS 表中的主键

select 
p1.Name As 1stName, p1.AccNo AS 1stAccNo, I1.ItemSold AS 1stItemSold, 
p2.Name AS 2ndName, p2.AccNo AS 2ndAccNo, I2.ItemSold As 2ndItemSold
FROM Persons p1 JOIN Persons p2 ON p1.AccNo = p2.AccNo 
INNER JOIN Items I1 on p1.ItemID = I1.ItemID
INNER JOIN Items I2 on p2.ItemID = I2.ItemID
where p1.id<>p2.id

PS：根据评论。返回最后一个 ItemSold 以避免重复：

select 
p1.Name As 1stName, p1.AccNo AS 1stAccNo, I1.ItemSold AS 1stItemSold, 
p2.Name AS 2ndName, p2.AccNo AS 2ndAccNo, I2.ItemSold As 2ndItemSold
FROM Persons p1 JOIN Persons p2 ON p1.AccNo = p2.AccNo 
left JOIN 
   (select ItemID,ItemSold, 
           row_number() over (PARTITION BY ItemID order by DATE_SOLD DESC) as rn 
    from Items) I1 
         on (p1.ItemID = I1.ItemID) and (rn=1)
left JOIN 
   (select ItemID,ItemSold, 
           row_number() over (PARTITION BY ItemID order by DATE_SOLD DESC) as rn 
    from Items) I2 
         on (p2.ItemID = I2.ItemID) and (rn=1)

where p1.id<>p2.id
于 2012-09-20T10:10:32.493 回答
1

我可能会误解您的要求，但听起来您可以使用该UNPIVOT/PIVOT功能来获得所需的结果。

如果您知道要转换的列数，那么您可以硬编码它的静态版本。

select *
from
(
  select AccNo,
    val,
    col + cast(rn as varchar(10)) Col_Name
  from
  (
    select p1.accno,
      p1.name,
      p1.itemid,
      i1.id,
      i1.i_name,
      row_number() over(partition by accno order by name) rn
    from persons p1
    left join items i1
      on p1.itemid = i1.id
  ) x
  unpivot
  (
    val
    for col in (name, i_name)
  ) u
) x1
pivot
(
  max(val)
  for col_name in ([name1], [i_name1], [name2], [i_name2])
) p

见SQL Fiddle with Demo

但听起来您将有未知数量的项目转换为列，因此您可以使用动态 SQL 并创建一个动态版本：

DECLARE @colsUnPivot AS NVARCHAR(MAX),
    @colsPivot AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

SET @colsUnPivot = stuff((select ','+C.name
         from sys.columns as C
         where (C.object_id = object_id('persons') 
                  or C.object_id = object_id('items'))
            and C.name like '%name%'
         for xml path('')), 1, 1, '')

select @colsPivot = STUFF((SELECT  ',' 
                      + quotename(c.name 
                         + cast(p.rn as varchar(10)))
                    from
                    (
                      select row_number() over(partition by accno order by name) rn
                      from persons
                    ) p
                     cross apply 
                      sys.columns as C
                   where (C.object_id = object_id('persons') 
                            or C.object_id = object_id('items'))
                      and C.name like '%name%'
                   group by c.name, p.rn
                   order by p.rn, c.name desc
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query 
  = 'select *
      from
      (
          select AccNo,
            val,
            col + cast(rn as varchar(10)) Col_Name
        from 
        (
          select p1.accno,
            p1.name,
            p1.itemid,
            i1.id,
            i1.i_name,
            row_number() over(partition by accno order by name) rn
          from persons p1
          left join items i1
            on p1.itemid = i1.id
        ) x
        unpivot
        (
          val
          for col in ('+ @colsunpivot +')
        ) u
      ) x1
      pivot
      (
        max(val)
        for col_name in ('+ @colsPivot + ')
      )p'

exec(@query)

见SQL Fiddle with Demo

于 2012-09-20T10:57:59.583 回答