需要 iOS6，所以如果我的identifierForVendor应用程序当前支持 iOS4，因此我不能使用它，因为我的更新应该总是满足我的应用程序之前的最低要求。要求？
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5 回答
28
你可以使用这个：
NSString *udid;
if (SYSTEM_VERSION_GREATER_THAN_OR_EQUAL_TO(@"6.0"))
udid = [UIDevice currentDevice].identifierForVendor.UUIDString;
else
udid = [UIDevice currentDevice].uniqueIdentifier;
带有预处理器代码：
#define SYSTEM_VERSION_EQUAL_TO(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedSame)
#define SYSTEM_VERSION_GREATER_THAN(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedDescending)
#define SYSTEM_VERSION_GREATER_THAN_OR_EQUAL_TO(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] != NSOrderedAscending)
#define SYSTEM_VERSION_LESS_THAN(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedAscending)
#define SYSTEM_VERSION_LESS_THAN_OR_EQUAL_TO(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] != NSOrderedDescending)
于 2012-09-27T22:06:25.627 回答
7
您不需要预处理器宏，您应该检查它是否响应，如下所示：
if ([[UIDevice currentDevice]respondsToSelector:@selector(identifierForVendor)]) {
return [UIDevice currentDevice].identifierForVendor.UUIDString;
}else{
// return [UIDevice currentDevice]. uniqueIdentifier
return [[UIDevice currentDevice] performSelector:@selector(uniqueIdentifier)];
}
于 2013-12-03T09:28:20.433 回答
2
它总是不同的。UUID 包含时间戳，因此每次调用此函数时，都会得到一个不同的（随机）。我在IDManager课堂上遵循了这种方法，这是来自不同解决方案的集合。KeyChainUtil 是一个从钥匙串中读取的包装器。在github中可以找到类似的钥匙串工具。
// IDManager.m
/*
A replacement for deprecated uniqueIdentifier API. Apple restrict using this from 1st May, 2013.
We have to consider,
* iOS <6 have not the ASIIdentifer API
* When the user upgrade from iOS < 6 to >6
- Check if there is a UUID already stored in keychain. Then use that.
- In that case, this UUID is constant for whole device lifetime. Keychain item is not deleted with application deletion.
*/
#import "IDManager.h"
#import "KeychainUtils.h"
#import "CommonUtil.h"
#if __IPHONE_OS_VERSION_MAX_ALLOWED >= 60000
#import <AdSupport/AdSupport.h>
#endif
#include <sys/socket.h>
#include <sys/sysctl.h>
#include <net/if.h>
#include <net/if_dl.h>
/* Apple confirmed this bug in their system in response to a Technical Support Incident request. They said that identifierForVendor and advertisingIdentifier sometimes returning all zeros can be seen both in development builds and apps downloaded over the air from the App Store. They have no work around and can't say when the problem will be fixed. */
#define kBuggyASIID @"00000000-0000-0000-0000-000000000000"
#pragma mark
#pragma mark
@implementation IDManager
+ (NSString *) getUniqueID {
#if __IPHONE_OS_VERSION_MAX_ALLOWED >= 60000
if (NSClassFromString(@"ASIdentifierManager")) {
NSString * asiID = [[[ASIdentifierManager sharedManager] advertisingIdentifier] UUIDString];
if ([asiID compare:kBuggyASIID] == NSOrderedSame) {
NSLog(@"Error: This device return buggy advertisingIdentifier.");
return [IDManager getUniqueUUID];
} else {
return asiID;
}
} else {
#endif
return [IDManager getUniqueUUID];
#if __IPHONE_OS_VERSION_MAX_ALLOWED >= 60000
}
#endif
}
+ (NSString *) getUniqueUUID
{
NSError * error;
NSString * uuid = [KeychainUtils getPasswordForUsername:@"UserName" andServiceName:@"YourServiceName" error:&error];
if (error) {
NSLog(@"Error geting unique UUID for this device! %@", [error localizedDescription]);
return nil;
}
if (!uuid) {
DLog(@"No UUID found. Creating a new one.");
uuid = [IDManager getUUID];
uuid = [CommonUtil md5String:uuid]; // create md5 hash for security reason
[KeychainUtils storeUsername:@"UserName" andPassword:uuid forServiceName:@"YourServiceName" updateExisting:YES error:&error];
if (error) {
NSLog(@"Error geting unique UUID for this device! %@", [error localizedDescription]);
return nil;
}
}
return uuid;
}
+ (NSString *) readUUIDFromKeyChain {
NSError * error;
NSString * uuid = [KeychainUtils getPasswordForUsername:@"UserName" andServiceName:@"YourServiceName" error:&error];
if (error) {
NSLog(@"Error geting unique UUID for this device! %@", [error localizedDescription]);
return nil;
}
return uuid;
}
/* NSUUID is after iOS 6. So we are using CFUUID for compatibility with iOS 4.3 */
+ (NSString *)getUUID
{
CFUUIDRef theUUID = CFUUIDCreate(NULL);
CFStringRef string = CFUUIDCreateString(NULL, theUUID);
CFRelease(theUUID);
return [(NSString *)string autorelease];
}
#pragma mark - MAC address
/* THIS WILL NOT WORK IN iOS 7. IT WILL RETURN A CONSTANT MAC ADDRESS ALL THE TIME.
SEE - https://developer.apple.com/news/?id=8222013a
*/
// Return the local MAC address
// Courtesy of FreeBSD hackers email list
// Last fallback for unique identifier
+ (NSString *) getMACAddress
{
int mib[6];
size_t len;
char *buf;
unsigned char *ptr;
struct if_msghdr *ifm;
struct sockaddr_dl *sdl;
mib[0] = CTL_NET;
mib[1] = AF_ROUTE;
mib[2] = 0;
mib[3] = AF_LINK;
mib[4] = NET_RT_IFLIST;
if ((mib[5] = if_nametoindex("en0")) == 0) {
printf("Error: if_nametoindex error\n");
return NULL;
}
if (sysctl(mib, 6, NULL, &len, NULL, 0) < 0) {
printf("Error: sysctl, take 1\n");
return NULL;
}
if ((buf = malloc(len)) == NULL) {
printf("Error: Memory allocation error\n");
return NULL;
}
if (sysctl(mib, 6, buf, &len, NULL, 0) < 0) {
printf("Error: sysctl, take 2\n");
free(buf); // Thanks, Remy "Psy" Demerest
return NULL;
}
ifm = (struct if_msghdr *)buf;
sdl = (struct sockaddr_dl *)(ifm + 1);
ptr = (unsigned char *)LLADDR(sdl);
NSString *outstring = [NSString stringWithFormat:@"%02X:%02X:%02X:%02X:%02X:%02X",
*ptr, *(ptr+1), *(ptr+2), *(ptr+3), *(ptr+4), *(ptr+5)];
free(buf);
return outstring;
}
+ (NSString *) getHashedMACAddress
{
NSString * mac = [IDManager getMACAddress];
return [CommonUtil md5String:mac];
}
@end
于 2013-05-13T15:06:01.930 回答
1
您可以使用以下代码
if (NSClassFromString(@"ASIdentifierManager")) {
return [[[ASIdentifierManager sharedManager] advertisingIdentifier] UUIDString];
} else {
// return other identifier generated with OpenUDID or some custom method
}
您可以在此处获取 OpenUDID 文档
于 2012-09-26T14:22:07.717 回答
0
看看NSSelectorFromString和 [NSObject performSelector:SEL]。NSSelectorFromString允许您通过运行时使用字符串选择选择器。将它与运行时的操作系统版本检查结合使用。
于 2012-09-20T06:18:04.450 回答