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所以我正在构建一个工具，它可以即时创建一个 ContentProject 然后构建它（以便它输出 Xnb） 目前的问题是，如果用CopyToOutputDirectory = 'always' 或 'PreserveNewest'。如果我们在 .contentProj 中查看不应该构建但应该复制的文件的该部分，则看起来像这样

<ItemGroup>
 <None Include="MyFile.file">
   <Name>level1</Name>
   <Importer>XmlImporter</Importer>
   <Processor>PassThroughProcessor</Processor>
   <CopyToOutputDirectory>PreserveNewest</CopyToOutputDirectory>
 </None>

但是，我正在即时构建内容项目，因此我需要以下代码来创建项目并添加项目

   var projectPath = Path.Combine(buildDirectory, "content.contentproj");
_projectRootElement = ProjectRootElement.Create(projectPath);

        _projectRootElement.AddImport("$(MSBuildExtensionsPath)\\Microsoft\\XNA Game Studio\\v4.0\\Microsoft.Xna.GameStudio.ContentPipeline.targets");

        _contentProject = new Project(_projectRootElement);

        _contentProject.SetProperty("XnaPlatform", "Windows");
        _contentProject.SetProperty("XnaProfile", "HiDef");
        _contentProject.SetProperty("XnaFrameworkVersion", "v4.0");
        _contentProject.SetProperty("Configuration", "Debug");
        _contentProject.SetProperty("OutputPath", _outputDirectory);

        // Register any custom importers or processors.
        foreach (string pipelineAssembly in PipelineAssemblies)
        {
            _contentProject.AddItem("Reference", pipelineAssembly);
        }

        // Hook up our custom error logger.
        _errorLogger = new ErrorLogger();
        _buildParameters = new BuildParameters(ProjectCollection.GlobalProjectCollection)
                            {
                                Loggers = new ILogger[] { _errorLogger,  }
                            };
//.... removed code that is not required the following is code that adds each item to the project. In case of items that shoulndt compile I m using None (as in xml from project above)

        var itemType = compile ? "Compile" : "None";

        var items = _contentProject.AddItem(itemType, filename);
        var item = items.SingleOrDefault(x => x.EvaluatedInclude.Equals(filename, StringComparison.InvariantCultureIgnoreCase));

        item.SetMetadataValue("Link", Path.GetFileName(filename));
        item.SetMetadataValue("Name", Path.GetFileNameWithoutExtension(filename));

        if (!compile)
            item.SetMetadataValue("CopyToOutputDirectory", "Always");

最后是构建代码

BuildManager.DefaultBuildManager.BeginBuild(_buildParameters);

        var request = new BuildRequestData(_contentProject.CreateProjectInstance(), new string[0]);

        var submission = BuildManager.DefaultBuildManager.PendBuildRequest(request);

        var execute = Task.Factory.StartNew(() => submission.ExecuteAsync(null, null), cancellationTokenSource.Token);
        var endBuild = execute.ContinueWith(ant => BuildManager.DefaultBuildManager.EndBuild());

        endBuild.Wait();

在 BuildRequest 中，空数组接受作为目标的参数......我已经经历了许多不同的目标，它们做不同的事情，从构建但没有真正输出文件到将依赖 dll 复制到主文件夹但不是我需要的

干杯

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0 回答 0