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我有一个通过 jQuery AJAX 调用从 PHP 脚本返回的二维 JSON 数组。我一直在四处浏览，试图找出如何遍历每一行并在 div 中显示每个条目，但我很困惑，不确定如何在这种特殊情况下执行此操作。

以下是服务器返回的 JSON 示例：

{"location_id":"505","location_name":"University of the Arts London","location_type":"uni","location_num_listings":"22","location_num_users":"187","relevancy":"2"},
    {"location_id":"592","location_name":"London South Bank University","location_type":"uni","location_num_listings":"1","location_num_users":"1","relevancy":"2"},
    {"location_id":"591","location_name":"London Metropolitan University","location_type":"uni","location_num_listings":"47","location_num_users":"185","relevancy":"2"},
    {"location_id":"590","location_name":"University College London","location_type":"uni","location_num_listings":"29","location_num_users":"176","relevancy":"2"},
    {"location_id":"586","location_name":"St George's, University of London","location_type":"uni","location_num_listings":"9","location_num_users":"4","relevancy":"2"},

到目前为止，这是我的脚本：

<script type="text/javascript">
    $("#directory_search_input").keyup(function() {
        $("#directory_search_results").html('');
        var regionvalue = $(this).val();
        var jsonresult;
        var url = '<?php echo site_url('ajax/ajax_default/directory_search')?>';
        $.post(url,{input_val:regionvalue}, function(data) {
            var results = jQuery.parseJSON(data);
            $.each(results, function() {
                $.each(this, function(index, value) {
                    $("#directory_search_results").append(/*Append a new div for each row returned*/);
                });
            }); });

示例所需的输出：

地点 ID：505，地点名称：伦敦艺术大学

地点 ID：592，地点名称：伦敦南岸大学

等等等等

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3 回答 3

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var results = $.parseJSON(data);
$.each(results, function(i, result) {
    $("#directory_search_results").append('<div>Location ID: '+result.location_id+' Location Name: '+result.location_name+'</div>');
});

​<a href="http://jsfiddle.net/JbaJP/">JSFiddle 示例

于 2012-09-19T11:58:04.587 回答
2 
$.each(data, function (index, value) {
            $("#SearchResults").append("<div>").append("Location Id  :" + value.location_id + ", Location Name : " + value.location_name ).append("\div");
});
于 2012-09-19T12:02:15.207 回答
1

假设您的 json 对象名为data，您可以执行以下操作：

$.each(data, function(key,value){
    //do all your code with key -> value pairs.
});

在这里看一个例子：http: //jsfiddle.net/3muwm/

当然这使用jQuery库

于 2012-09-19T12:43:33.703 回答