下面是一个用于在执行标记化的程序中获取下一个标记的函数。它目前正在运行，但我仍然不确定它是否符合我教授的要求。如果您查看顶部评论部分，他说“应该动态分配返回令牌的空间”。
每当我听说我希望我必须使用malloc时，但我没有使用malloc就做到了。我这样想对吗？
/*
* TKGetNextToken returns the next token from the token stream as a
* character string. Space for the returned token should be dynamically
* allocated. The caller is responsible for freeing the space once it is
* no longer needed.
*
* If the function succeeds, it returns a C string (delimited by '\0')
* containing the token. Else it returns 0.
*
* You need to fill in this function as part of your implementation.
*/
char *TKGetNextToken(TokenizerT *tk) {
char *sPtr, *tPtr, *delim, *temp = NULL, *ret = NULL;
sPtr = tk->sepr; //pointer to the separators
tPtr = tk->ts;
temp = tPtr;
while (tPtr[0] != '\0') //Scan tokenstream
{
delim = tk->sepr;
while (delim[0] != '\0') //scan separator stream
{
if (*tPtr == *delim) //Matched with a separator
{
if (tPtr == temp) //Check if beginning of the tokenstream
{
//then skip over this character.
temp++;
break; //Break loop because it may skip checking a char with a prev delim.
}
else
{
//Cut off current position with null character and pass over it.
*tPtr = '\0';
tPtr++;
if((ret = malloc(sizeof temp) + 1 * sizeof(char)) != NULL) //add 1 for null character '\0'
strcpy(ret, temp);
tk->ts = tPtr; //In position for next token.
return ret;
}
}
else
{
delim++; //Go to next separator.
}
}
tPtr++; //Go to next character.
count++;
}
if((ret = malloc(sizeof temp) + 1 * sizeof(char)) != NULL) //add 1 for null character '\0'
strcpy(ret, temp);
tk->ts = tPtr;
return ret;
}
编辑：所以我想我修复了它，但很好奇，像我一样使用 malloc ，这不是只为指针地址而不是整个令牌分配空间吗？