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我是 SO 和 postgres 的新手,所以请原谅我的无知。尝试使用类似于本文中的解决方案在 postgres 中获取图形的集群Find cluster given node in PostgreSQL

唯一的区别是我的 id 是一个 UUID,我使用 varchar(255) 来存储这个 id

当我尝试运行查询时,出现以下错误(但不确定如何转换):

ERROR: recursive query "search_graph" column 1 has type character varying(255)[] in non-recursive term but type character varying[] overall

SQL 状态:42804 提示:将非递归项的输出转换为正确的类型。人物:81

我的代码(与之前的帖子基本相同):

WITH RECURSIVE search_graph(path, last_profile1, last_profile2) AS (
SELECT ARRAY[id], id, id
FROM node WHERE id = '408d6b12-d03e-42c2-a2a7-066b3c060a0b'
UNION ALL
SELECT sg.path || m.toid || m.fromid, m.fromid, m.toid
FROM search_graph sg
JOIN rel m
ON (m.fromid = sg.last_profile2 AND NOT sg.path @> ARRAY[m.toid]) 
   OR (m.toid = sg.last_profile1 AND NOT sg.path @> ARRAY[m.fromid])
)

 SELECT DISTINCT unnest(path) FROM search_graph;
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1 回答 1

11

尝试SELECT将递归和非递归术语中的列表转换为varchar.

WITH RECURSIVE search_graph(path, last_profile1, last_profile2) AS (
    SELECT ARRAY[id]::varchar[], id::varchar, id::varchar
    FROM node WHERE id = '408d6b12-d03e-42c2-a2a7-066b3c060a0b'
  UNION ALL
    SELECT (sg.path || m.toid || m.fromid)::varchar[], m.fromid::varchar, m.toid::varchar
    FROM search_graph sg
    JOIN rel m
    ON (m.fromid = sg.last_profile2 AND NOT sg.path @> ARRAY[m.toid]) 
       OR (m.toid = sg.last_profile1 AND NOT sg.path @> ARRAY[m.fromid])
)
SELECT DISTINCT unnest(path) FROM search_graph;
于 2012-09-19T04:13:05.693 回答