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我用 C# 为我的 Arduino 做了一个小应用程序。一切正常,但问题出在我的应用程序中。用户可以在 numericUpDown 中选择他/她的 COM 端口。

它可以工作,但是如果用户选择了错误的端口并尝试连接,它就会崩溃,所以我想我需要一个 IF statmant 来提供消息。比如端口不对等,但是不知道怎么弄。我该怎么做?

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.IO;
using System.IO.Ports;

namespace IO_Arduino_experiment_project
{
    public partial class Form1 : Form
    {
        public static System.IO.Ports.SerialPort serialPort1;
        private delegate void LineReceivedEvent(string line);
        public Form1()
        {
            InitializeComponent();
            button5.Enabled = false;
            button2.Enabled = false;
            button3.Enabled = false;
        }

        private void button1_Click(object sender, EventArgs e) // Connect Button
        {
            System.ComponentModel.IContainer components = new System.ComponentModel.Container();
            serialPort1 = new System.IO.Ports.SerialPort(components); // Creating the new object.
            serialPort1.PortName = "COM" + numericUpDown1.Value.ToString(); // Setting what port number.
            serialPort1.BaudRate = 9600;
            serialPort1.DtrEnable = true;
            serialPort1.Open(); // Open the port for use.
            button1.Text = "Connected.";
            button1.Enabled = false;
            numericUpDown1.Enabled = false;
            button5.Enabled = true;
            button2.Enabled = true;
            button3.Enabled = true;
        }

        private void numericUpDown1_ValueChanged(object sender, EventArgs e)
        {

        }

        private void Form1_FormClosing(object sender, FormClosingEventArgs e)
        {
            if (serialPort1.IsOpen) serialPort1.Close();
        }

        private void button2_Click(object sender, EventArgs e)
        {
            serialPort1.Write("1");
            textBox1.Text = "LED is on!";
            button2.Enabled = false;
            button3.Enabled = true;
        }

        private void button3_Click(object sender, EventArgs e)
        {
            serialPort1.Write("0");
            textBox1.Text = "LED is off!";
            button2.Enabled = true;
            button3.Enabled = false;
        }

        private void button4_Click(object sender, EventArgs e)
        {
            Close();
        }

        private void button5_Click(object sender, EventArgs e)
        {
            serialPort1.Close();
            button1.Enabled = true;
            numericUpDown1.Enabled = true;
        }
    }
}
4

1 回答 1

1

ComboBox您真的应该用表单打开或单击刷新按钮时(或通过其他自动方式,如计时器)填充的或其他列表控件/菜单替换数字向上/向下。

ComboBoxList可以使用以下方法填充:GetPortNames-

String[] pNames;
pNames = System.IO.Ports.SerialPort.GetPortNames();

如果您想做您所描述的事情,那么您可以使用类似的代码在尝试使用之前查找端口以查看它是否存在:-

if (System.IO.Ports.SerialPort.GetPortNames().indexOf("COM" +  thePortNum.ToString())>-1)

请注意,GetPortNames()返回这样的列表:-

 COM1
 COM10
 COM12
于 2012-09-19T16:44:09.957 回答