mysql - 日期查询之间的 MySQL 无法正常工作

Question

我正在努力完成这项工作，这个查询应该给出两个日期之间最便宜的价格，但不知何故它总是给出最便宜的报价，它有点忽略日期

SELECT offer_id 
FROM travel_offers o
WHERE price = (
    SELECT MIN(price) as minprice 
    FROM travel_offers om 
    WHERE 
        o.latitude = om.latitude AND
        o.longitude = om.longitude AND
        (o.time_from BETWEEN '2012-07-01' AND '2012-11-31') 
        AND
        (o.time_to BETWEEN '2012-07-01' AND '2012-11-31')
)

Answer 1

如果经度和纬度很重要，试试这个：

SELECT o.longitude, o.latitude, offer_id 
FROM travel_offers o
WHERE o.time_from BETWEEN '2012-07-01' AND '2012-11-31'
      AND o.time_to BETWEEN '2012-07-01' AND '2012-11-31')
      AND price = (
     SELECT MIN(price) as minprice 
     FROM travel_offers om 
     WHERE 
        o.latitude = om.latitude AND
        o.longitude = om.longitude AND
        (om.time_from BETWEEN '2012-07-01' AND '2012-11-31') 
        AND
        (om.time_to BETWEEN '2012-07-01' AND '2012-11-31')
)

如果经度和纬度无关紧要：

SELECT offer_id 
FROM travel_offers o
WHERE o.time_from BETWEEN '2012-07-01' AND '2012-11-31'
      AND o.time_to BETWEEN '2012-07-01' AND '2012-11-31')
      AND price = (
     SELECT MIN(price) as minprice 
     FROM travel_offers om 
     WHERE 
        (om.time_from BETWEEN '2012-07-01' AND '2012-11-31') 
        AND
        (om.time_to BETWEEN '2012-07-01' AND '2012-11-31')
)

Answer 2

不知何故，它总是提供最便宜的报价，而且它有点忽略了日期

我猜你1time_from应该是2012-07-01而且time_to应该是2012-11-31。
因此，您需要像这样更正WHERE子句中1time_from的条件1time_to：

WHERE 
    o.latitude = om.latitude AND
    o.longitude = om.longitude AND
    (o.time_from >= '2012-07-01') 
    AND
    (o.time_to <= '2012-11-31')

Answer 3

SELECT offer_id, MIN(price) as minprice 
FROM travel_offers
WHERE 
    time_from BETWEEN '2012-07-01' AND '2012-11-31'
    AND
    time_to BETWEEN '2012-07-01' AND '2012-11-31'
    and 
    time_from <= time_to
group by offer_id
order by minprice
limit 1