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我想使用下面的 jQuery 对话框来打开不同的弹出框

<head runat="server">
    <title></title>
    <link href="css/ui-lightness/jquery-ui-1.7.2.custom.css" rel="stylesheet" type="text/css" />
    <script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>
    <script src="js/jquery-ui-1.7.2.custom.min.js" type="text/javascript"></script>
    <script type="text/javascript">
        $(document).ready(function () {
            $("#pop101").dialog({
                autoOpen: false,
                draggable: true,
                title: "Add New Person",
                open: function (type, data) {
                     $(this).parent().appendTo("form");
                }
            });
        });
        function showDialog(id) {
            $('#' + id).dialog("open");
        }
        function closeDialog(id) {
            $('#' + id).dialog("close");
        }
    </script>
</head>
<body>
    <input type="button" onclick="showDialog('pop101');" value="Popup1" />
    <input type="button" onclick="showDialog('pop102');" value="Popup2" />
    <input type="button" onclick="showDialog('pop103');" value="Popup3" />
    <input type="button" onclick="showpopup('pop104');" value="Popup4" />
    <div style="background: green" id='pop101'>
    </div>
    <div style="background: orange" id='pop102'>
    </div>
    <div style="background: blue" id='pop103'>
    </div>
    <div style="background: skyblue" id='dialog1'>
    </div>
</body>

有 4 个按钮 popup1,2,3,4 ，当我点击它们时，弹出窗口应该使用上面的代码显示，如何？

4

1 回答 1

1

尝试使用一个类来初始化弹出窗口：

尚未尝试但应该可以：

<head runat="server">
    <title></title>
    <link href="css/ui-lightness/jquery-ui-1.7.2.custom.css" rel="stylesheet" type="text/css" />
    <script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>
    <script src="js/jquery-ui-1.7.2.custom.min.js" type="text/javascript"></script>
    <script type="text/javascript">
        $(document).ready(function () {
            $(".popup").dialog({
                autoOpen: false,
                draggable: true,
                title: "Add New Person",
                open: function (type, data) {
                    $(this).parent().appendTo("form");
                }
            });
        });
        function showDialog(id) {
            $('#' + id).dialog("open");
        }
        function closeDialog(id) {
            $('#' + id).dialog("close");
        }
    </script>
</head>
<body>
    <input type="button" onclick="showDialog('pop101');" value="Popup1" />
    <input type="button" onclick="showDialog('pop102');" value="Popup2" />
    <input type="button" onclick="showDialog('pop103');" value="Popup3" />
    <input type="button" onclick="showpopup('pop104');" value="Popup4" />
    <div style="background: green" id='pop101' class="popup">
    </div>
    <div style="background: orange" id='pop102' class="popup">
    </div>
    <div style="background: blue" id='pop103' class="popup">
    </div>
    <div style="background: skyblue" id='dialog1' class="popup">
    </div>
</body>

这是小提琴；有效！！

于 2012-09-18T10:30:11.670 回答