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我想从以下 InputStream 中获取“SearchResult”值:

HTTP/1.1 200 OK
Content-Type: application/soap+xml; charset=utf-8
Content-Length: length

<?xml version="1.0" encoding="utf-8"?>
<soap12:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap12="http://www.w3.org/2003/05/soap-envelope">
    <soap12:Body>
        <SearchResponse xmlns="[url here]">
            <SearchResult>[THIS VALUE HERE]</SearchResult>
        </SearchResponse>
      </soap12:Body>
</soap12:Envelope>

我一直在尝试使用 DOM 解析器,但遇到了麻烦,并且不确定它是否是正确的方法:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder db;
Document doc = null;

db = factory.newDocumentBuilder();
InputSource inStream = new InputSource();
inStream.setCharacterStream(new StringReader(soapResponse));
doc = db.parse(inStream);  

NodeList nl = doc.getElementsByTagName("SearchResult");
//Not sure how to get the value... Everything I've tried returned "null". Help?

我怎样才能做到这一点?

4

1 回答 1

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对于 Java 和 Android 8 级或更高版本: nodeList.item(0).getTextContent()

对于 android 级别 1 及更高版本: nodeList.item(0).getFirstChild().getNodeValue()

于 2012-09-17T20:43:20.483 回答