假设我向我的 API 发送了以下请求:
POST http://localhost:4940/api/cars HTTP/1.1
User-Agent: Fiddler
Host: localhost:4940
Content-Type: application/json
Content-Length: 44
{"Make":"Make1","Year":2010,"Price":10732.2}
我有以下 Car 类定义:
public class Car {
public int Id { get; set; }
[Required]
[StringLength(20)]
public string Make { get; set; }
[Required]
[StringLength(20)]
public string Model { get; set; }
public int Year { get; set; }
[Range(0, 500000)]
public float Price { get; set; }
}
我得到的回复如下:
HTTP/1.1 400 Bad Request
Cache-Control: no-cache
Pragma: no-cache
Content-Type: application/json; charset=utf-8
Expires: -1
Server: Microsoft-IIS/8.0
X-AspNet-Version: 4.0.30319
X-SourceFiles: =?UTF-8?B?RTpcRHJvcGJveFxCb29rc1xQcm9XZWJBUEkuU2FtcGxlc1xDaGFwdGVyMTNcRGF0YUFubm90YXRpb25WYWxpZGF0aW9uQXR0cmlidXRlc1NhbXBsZVxEYXRhQW5ub3RhdGlvblZhbGlkYXRpb25BdHRyaWJ1dGVzU2FtcGxlXGFwaVxjYXJz?=
X-Powered-By: ASP.NET
Date: Mon, 17 Sep 2012 11:38:58 GMT
Content-Length: 182
{"Message":"The request is invalid.","ModelState":{"car":["Required property 'Model' not found in JSON. Path '', line 1, position 44."],"car.Model":["The Model field is required."]}}
以下是更易读的消息正文形式:
{
"Message": "The request is invalid.",
"ModelState": {
"car": [
"Required property 'Model' not found in JSON. Path '', line 1, position 44."
],
"car.Model":[
"The Model field is required."
]
}
}
正如您所看到的,我还有一条关于汽车的附加错误消息,我猜测JsonMediaTypeFormatter
执行验证也是如此,但它无法执行读取操作。
这是这里的问题吗?有什么方法可以抑制 JsonMediaTypeFormatter 级别的验证?我不希望格式化程序执行验证,因为验证也是由IBodyModelValidator
格式化程序读取消息正文后执行的。
编辑:
我调试了源代码,JsonMediaTypeFormatter
如果属性标记为必需但未提供,它会抛出错误。以下代码是以下代码的一部分JsonMediaTypeFormatter
:
// Error must always be marked as handled
// Failure to do so can cause the exception to be rethrown at every recursive level and overflow the stack for x64 CLR processes
jsonSerializer.Error += (sender, e) =>
{
Exception exception = e.ErrorContext.Error;
formatterLogger.LogError(e.ErrorContext.Path, exception);
e.ErrorContext.Handled = true;
}
这会触发ModelStateFormatterLogger.LogError
将错误放入的方法ModelState
:
public void LogError(string errorPath, Exception exception)
{
if (errorPath == null)
{
throw Error.ArgumentNull("errorPath");
}
if (exception == null)
{
throw Error.ArgumentNull("exception");
}
string key = ModelBindingHelper.ConcatenateKeys(_prefix, errorPath);
_modelState.AddModelError(key, exception);
}
我仍然无法抑制这种行为。