1

这是我的 Android main.java 我从这里调用 web 服务。但是我有一些问题,但我不知道哪个是失败的。我正在使用 android 调试器,但它在 transpor.call() 行中停止...

谢谢大家

package org.exa.prueba2android;


import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;

import org.ksoap2.transport.HttpTransportSE;

import android.app.Activity;
import android.os.Bundle;


import android.widget.TextView;


public class Main extends Activity {

    private static final String accionSoap="http://CartaWS.restaurante.org/showItems";
    private static final String Metodo = "showItems";
    private static final String namespace="http://CartaWS.restaurante.org";
    private static final String url="http://192.168.2.5:8080/CartaWSPrueba/services/CartaWS.CartaWSHttpSoap11Endpoint/";



    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        TextView tv = (TextView) findViewById(R.id.text);

        try{

            SoapObject request= new SoapObject(namespace, Metodo);
            //modelo sobre
            SoapSerializationEnvelope sobre = new SoapSerializationEnvelope(SoapEnvelope.VER11);
            sobre.dotNet = true;
            sobre.setOutputSoapObject(request);

            HttpTransportSE transporte = new HttpTransportSE(url);
            //LLAMADA 



            //   **HERE IS THE PROBLEM**


             transporte.call(accionSoap, sobre)`;






        //Result
        SoapPrimitive result = (SoapPrimitive)sobre.getResponse();
        tv.setText("BEBIDAS: "+result.toString());


        } catch (Exception e){}

    }

}

我正在使用 Tomcat7、axis2、java、android、ksoap 2.6.1。Android 调试器停在这一行

transporte.call(accionSoap, sobre);

或者下一个

SoapPrimitive result = (SoapPrimitive)sobre.getResponse();

我是新来的,谢谢你所做的一切。

4

0 回答 0