sql - SQL - 按总计对结果进行分组

Question

下面的查询给了我两列的输出：

Day Num_Users_Retained
0   209312
1   22139
2   11457

依此类推，一直到 259（2012 年的每一天）..但是我希望第 0 天包含 num_users_retained 中从 0 到 259 的所有值的总和...然后我希望第 1 天包含从 1 到 259 的所有值的总和，依此类推，直到我到达最后一天。这是原始查询：

--Retention since January 1,2012--
select retention as Day,count(retention) as Num_Users_Retained
from (select player_id,round(init_dtime-create_dtime,0) as retention
from player
where Trunc(Create_Dtime) >= To_Date('2012-jan-01','yyyy-mon-dd')
and init_dtime is not null)
Group by retention
order by 1 

有什么建议么？

Answer 1

使用分析函数

select
    day,
    num_users_retained,
    sum(num_users_retained) over (order by day) as total_num_users_retained
from churn

http://www.sqlfiddle.com/#!4/24e02/1

此查询写入您的结果集。您可以将其应用于您的原始查询。

Answer 2

select retention as Day
     , Sum(count(retention)) over(order by retention desc) as Num_Users_Retained
 from (select player_id
            , round(init_dtime-create_dtime,0) as retention
        from player
       where Trunc(Create_Dtime) >= To_Date('2012-jan-01','yyyy-mon-dd')
         and init_dtime is not null
       )
Group by retention
order by retention