php - 如何在项目之间用逗号打印PHP结果但不是在最后

Question

我得到它显示所有在线用户，但我将如何为最后一个在线用户制作它，最后去掉逗号。这是我的代码

                    while($online = mysql_fetch_array($usersonline)){
                    $username = $online['username'];

                    echo"<b> $username, </b>";
                    }

Answer 1

我建议使用内爆方法：

$usernames = [];

while($online = mysql_fetch_array($usersonline)){
  array_push($usernames, $online['username']);
}

echo implode(',', $usernames);

Answer 2

只需对索引进行操作并在之前而不是之后追加，就像这样

$index = 0;
while($online = mysql_fetch_array($usersonline)) {
  $username = $online['username'];
  echo"<b> ".($index>0?',':'')." {$username}</b>";
  $index++;
}

Answer 3

    $u = 0;
    while($online = mysql_fetch_array($usersonline))
    {
        $u++;
        if($u == 1){
            $usernames = '<b>' . $online['username'] . '</b>';
        }else{
            $usernames .= '<b>, ' . $online['username'] . '</b>';
        }
    }

编辑：内爆可能会更好。

Answer 4

$join = '';
while($online = mysql_fetch_array($usersonline))
{
    $username = $online['username'];
    echo"<b> $join . $username </b>";
    $join = ',';
}

或者

$out = '';
while($online = mysql_fetch_array($usersonline))
{
    $username = $online['username'];
    $out .="<b> $username </b>,";
}
$out = rtrim($out,",");
echo $out;

或作为“tehlulz”建议

$usernames = [];

while($online = mysql_fetch_array($usersonline)){
  array_push($usernames, $online['username']);
}

echo implode(',', $usernames);

Answer 5

这可能不是最优雅的方式，但这应该有效：

$users="<b>";
while($online = mysql_fetch_array($usersonline))
{
    $username = $online['username'];
    $users.="$username,";
}
rtrim($users,',');
$users.="</b>";
echo $users;