7

我正在使用以下代码(显示在 WWDC 2012 视频中):

 self.accountStore = [[ACAccountStore alloc] init];

    ACAccountType *facebookAccountType = [self.accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierFacebook];

    [self.accountStore requestAccessToAccountsWithType:facebookAccountType
                                 withCompletionHandler:^(BOOL granted, NSError *e) {
                                     if (granted)
                                     {
                                         NSArray *accounts = [self.accountStore
                                                              accountsWithAccountType:facebookAccountType];
                                         self.facebookAccount = [accounts lastObject];
                                     } else {
                                         // Fail gracefully...
                                     }
                                 }];

我还添加了NSDictionary到我的.plist文件中:

在此处输入图像描述

所以,我的问题是我收到以下异常:

 *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Access options are required for this account type.'

我已经尝试过这个ACAccountTypeIdentifierTwitterACAccountTypeIdentifierSinaWeibo. 尽管他们总是返回,但我没有收到任何异常granted == NO

4

2 回答 2

17

好吧,WWDC 2012 显示了一件事,但文档显示了另一件事......他们使用的方法现在已弃用:

– requestAccessToAccountsWithType:withCompletionHandler: Deprecated in iOS 6.0

你应该做什么:

ACAccountType *facebookAccountType = [self.accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierFacebook];

    NSDictionary *options = @{
    @"ACFacebookAppIdKey" : @"123456789",
    @"ACFacebookPermissionsKey" : @[@"publish_stream"],
    @"ACFacebookAudienceKey" : ACFacebookAudienceEveryone}; // Needed only when write permissions are requested

    [self.accountStore requestAccessToAccountsWithType:facebookAccountType options:options 
                                 completion:^(BOOL granted, NSError *error) {
                                     if (granted)
                                     {
                                         NSArray *accounts = [self.accountStore
                                                              accountsWithAccountType:facebookAccountType];
                                         self.facebookAccount = [accounts lastObject];
                                     } else {
                                         NSLog(@"%@",error);
                                         // Fail gracefully...
                                     }
                                 }];
于 2012-09-16T21:20:10.240 回答
0

斯威夫特 3

let account = ACAccountStore()
let accountType = account.accountType(withAccountTypeIdentifier: ACAccountTypeIdentifierFacebook)
let options: [AnyHashable : Any] = [ACFacebookAppIdKey: "Your App ID on FB", ACFacebookPermissionsKey: ["publish_stream", "publish_actions"], ACFacebookAudienceKey: ACFacebookAudienceEveryone]

account.requestAccessToAccounts(with: accountType, options: options) { (success, error)  in
  if success {
    if let accounts = account.accounts(with: accountType) {
      if accounts.isEmpty {
        print("No facebook account found, please add your facebook account in phone settings")
      } else {
        let facebookAccount = accounts.first as! ACAccount

        let message = ["status": "My first Facebook posting "]
        let requestURL = URL(string: "https://graph.facebook.com/me/feed")

        let postRequest = SLRequest(forServiceType: SLServiceTypeFacebook,
                                    requestMethod: SLRequestMethod.POST,
                                    url: requestURL,
                                    parameters: message)
        postRequest?.account = facebookAccount

        postRequest?.perform(handler: {(_, urlResponse,
          error) in

          if let err = error {
            print("Error : \(err.localizedDescription)")
          }
          print("Facebook HTTP response \(String(describing: urlResponse?.statusCode))")
        })
      }
    }
  } else {
    print("Facebook account error: \(String(describing: error))")
  }
}
于 2017-08-04T06:53:36.940 回答