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我的脚本是 python，而 cassandra 是数据 stax 社区版。

TypeError: A str or unicode value was expected, but int was received instead (3902503)

这是我在尝试插入 cassandra 列族时遇到的错误。

代码是这样的：

for x in feed:
    cf.insert(uuid.uuid4(), x)

x 是“{key:value}”形式的简单数组

错误日志提示：

    Traceback (most recent call last):
      File "C:\Users\me\Desktop\pro1\src\pro1.py", line 73, in <module>
        str("swf"): str("aws")
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 969, in insert
        mut_list = self._make_mutation_list(columns, timestamp, ttl)
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 504, in _make_mutation_list
        columns.iteritems())
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 503, in <lambda>
        return map(lambda (c, v): Mutation(self._make_cosc(_pack_name(c), _pack_value(v, c), timestamp, ttl)),
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 462, in _pack_value
        return packer(value)
      File "c:\Python27\lib\site-packages\pycassa\marshal.py", line 231, in pack_bytes
        % (v.__class__.__name__, str(v)))
    TypeError: A str or unicode value was expected, but int was received instead (3902503)

我在这里似乎很想念一些东西……这就是我来这里问专家的原因！

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1 回答 1

4

确保您的值与您的列族类型相匹配。看来您的列族要么是 BytesType 要么没有与之关联的类型，因此 pycassa 将只接受字符串值。您可以将所有值映射到str带有嵌套字典理解的列表理解（后者需要 python 2.7 及更高版本）：

cf.insert(uuid.uuid4(), [{k: str(v) for k, v in d.iteritems()} for d in x])
于 2012-09-16T10:32:37.927 回答