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我正在使用 AFNetworking 的 AFHTTPClient 从我的 IOS 应用程序调用我的服务器，该服务器使用 Django 和 TastyPie。当我在服务器端关闭身份验证时，它工作得很好；但是，当我需要身份验证并将正确的用户名和密码插入我的代码时，我收到以下 401 身份验证错误：

\2012-09-16 00:24:37.877 RESTtest[76909:f803] 
Complex AF: Error Domain=AFNetworkingErrorDomain Code=-1011 
"Expected status code in (200-299), got 401" 
UserInfo=0x686ba00 {AFNetworkingOperationFailingURLResponseErrorKey=<NSHTTPURLResponse: 0x686f130>, 
NSErrorFailingURLKey=http://127.0.0.1:8000/api/v1/shoppinglist, 
NSLocalizedDescription=Expected status code in (200-299), got 401, 
AFNetworkingOperationFailingURLRequestErrorKey=<NSMutableURLRequest http://127.0.0.1:8000/api/v1/shoppinglist>}

这是我的代码：

AFAPIClient.h #import "AFHTTPClient.h"

@interface AFAPIClient : AFHTTPClient

-(void)setUsername:(NSString *)username andPassword:(NSString *)password;

+ (AFAPIClient *)sharedClient;

@end

AFAPIClient.m:

#import "AFAPIClient.h"
#import "AFJSONRequestOperation.h"


static NSString * const baseURL = @"http://@127.0.0.1:8000/api/v1";


@implementation AFAPIClient

+ (AFAPIClient *)sharedClient {
    static AFAPIClient *_sharedClient = nil;
    static dispatch_once_t pred;
    dispatch_once(&pred, ^{
        _sharedClient = [[AFAPIClient alloc] initWithBaseURL:[NSURL URLWithString:baseURL]];
        //[_sharedClient setAuthorizationHeaderWithUsername:@"myusername" password:@"mypassword"]; I tried putting the authorization command here
    });

    return _sharedClient;
};

#pragma mark - Methods

-(void)setUsername:(NSString *)username andPassword:(NSString *)password;
{
    [self clearAuthorizationHeader];
    [self setAuthorizationHeaderWithUsername:username password:password];
}

- (id)initWithBaseURL:(NSURL *)url
{
    self = [super initWithBaseURL:url];
    if (!self) {
        return nil;
    }

    [self registerHTTPOperationClass:[AFJSONRequestOperation class]];
    [self setParameterEncoding:AFJSONParameterEncoding];


    //[self setAuthorizationHeaderWithUsername:@"myusername" password:@"mypassword"]; I also tried putting the authorization command here

    // Accept HTTP Header; see http://www.w3.org/Protocols/rfc2616/rfc2616-sec14.html#sec14.1
    [self setDefaultHeader:@"Accept" value:@"application/json"];

    return self;
}


@end

TQViewController.h：

[...]
- (IBAction)sendAFClientRequest:(id)sender {
    //[[AFAPIClient sharedClient] setUsername:@"myusername" andPassword:@"mypassword"];
    [[AFAPIClient sharedClient] getPath:@"shoppinglist" parameters:nil success:^(AFHTTPRequestOperation *operation, id response) {
        NSLog(@"Complex AF: %@", [response valueForKeyPath:@"objects"]);
    } failure:^(AFHTTPRequestOperation *operation, id response) {
        NSLog(@"Complex AF: %@", response);
    }
     ];

}
[...]

我知道这不是我的服务器或我的用户名/密码的问题，因为我可以通过将用户名/密码插入 URL 来很好地进行身份验证：

@"http://myusername:mypassword@127.0.0.1:8000/api/v1/shoppinglist"

对此的任何帮助都会很棒。能够使用 AFHTTPClient 而不将身份验证信息直接插入静态基本 URL 会很棒，这似乎完全不合适。提前致谢！

4

1 回答 1

4

基于此：https ://github.com/AFNetworking/AFNetworking/issues/426

我重写了- (void)getPath:(NSString *)path parameters...AFHTTPClient 子类中的方法，使其看起来像这样：

- (void)getPath:(NSString *)path parameters:(NSDictionary *)parameters
    success:(void (^)(AFHTTPRequestOperation *operation, id responseObject))success
    failure:(void (^)(AFHTTPRequestOperation *operation, NSError *error))failure
{
    NSURLRequest *request = [self requestWithMethod:@"GET" path:path parameters:parameters];
    AFHTTPRequestOperation *operation = [self HTTPRequestOperationWithRequest:request success:success failure:failure];
    [operation setAuthenticationChallengeBlock:^(NSURLConnection *connection, NSURLAuthenticationChallenge *challenge) {
        NSURLCredential *newCredential = [NSURLCredential credentialWithUser:self.username password:self.password persistence:NSURLCredentialPersistenceForSession];
        [challenge.sender useCredential:newCredential forAuthenticationChallenge:challenge];
    }];
    [self enqueueHTTPRequestOperation:operation];
}

它只是将身份验证挑战块添加到 AFHTTPRequestOpertaion，其余与原始实现相同https://github.com/AFNetworking/AFNetworking/blob/master/AFNetworking/AFHTTPClient.m

于 2012-10-20T18:58:28.583 回答