5

有人知道吗？我通过了拼写检查“加速器”，这是一个非常好的词。我回来“加速”？当我在浏览器中打开 Google 并输入“加速器”时，它不会提示“加速器”？

using System;
using System.Net;
using System.Text;
using System.Text.RegularExpressions;

namespace SpellCheck
{
    class googel_SP
    {
        public string word;
        public void run_G()
        {
            string retValue = string.Empty;
            string Iword = "accelerants";

            try
            {
                string uri = "https://www.google.com/tbproxy/spell?lang=en:";
                using (WebClient webclient = new WebClient())
                {
                    string postData = string.Format("<?xml version=\"1.0\"     encoding=\"utf-8\" ?> " 
                    + "<spellrequest textalreadyclipped=\"0\" ignoredups=\"0\"     ignoredigits=\"1\" "
                    + "ignoreallcaps=\"1\"><text>{0}</text></spellrequest>", Iword);

                    webclient.Headers.Add("Content-Type", "application/x-www-form-    urlencoded");
                    byte[] bytes = Encoding.ASCII.GetBytes(postData);
                    byte[] response = webclient.UploadData(uri, "POST", bytes);
                    string data = Encoding.ASCII.GetString(response);
                    if (data != string.Empty)
                    {
                        retValue = Regex.Replace(data, @"<(.|\n)*?>",     string.Empty).Split('\t')[0];
                        Console.WriteLine(" word in -> " + word + " word out -> " +      retValue);
                    }
                }
            }
            catch (Exception exp)
            {

            }
            //return retValue;
        }
    }

 }
4

1 回答 1

3

有趣...我运行了您的代码，如果我故意将“促进剂”作为搜索词传递，它会正确返回“促进剂”。但是，如果我通过“加速器”，它会返回“加速器”。更改语言和文本编码似乎没有什么不同。

这是可以完成相同工作的替代代码..显然需要一些错误处理，但您明白了:)

string retValue = string.Empty;
word = "accelerants";

string uri = string.Format( "http://www.google.com/complete/search?output=toolbar&q={0}", word );

HttpWebRequest request = ( HttpWebRequest ) WebRequest.Create( uri );
HttpWebResponse response = ( HttpWebResponse ) request.GetResponse( );

using ( StreamReader sr = new StreamReader( response.GetResponseStream( ) ) ) {
    retValue = sr.ReadToEnd( );
}

XDocument doc = XDocument.Parse( retValue );

XAttribute attr = doc.Root.Element( "CompleteSuggestion" ).Element( "suggestion" ).Attribute( "data" );

string correctedWord = attr.Value;
于 2012-10-30T10:35:41.943 回答