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我在更大的查询中有以下子查询。我收到错误“子查询返回超过 1 个值”。我不确定如何解决这个问题，并且仍然会发生两个查询的结果划分。我正在使用 SQL Server 2005。

谢谢。

SELECT 
    sample_fields, -- some fields here
    (SELECT 
        c1/c2 AS department_occupancy_rate  -- doing division of results of both queries
     FROM 
        property as c
        JOIN (
               SELECT store_id, cast(count(*) as decimal(10,2)) AS c1
               FROM property 
               WHERE 
                   non_ha =1 
               AND property_type LIKE '%587%'     
               GROUP BY store_id
             ) AS sub1 
             ON c.store_id = sub1.store_id
             JOIN (
                SELECT store_id, cast(count(*) as decimal(10,2)) AS c2
                FROM property 
                WHERE 
                    property_type LIKE '%587%'
                GROUP BY store_id
             ) AS sub2 
             ON c.store_id = sub2.store_id
        ) as results,
FROM 
    sample_table -- a table here
    INNER JOIN sample_table1 
    ON sample_table2 -- joining here
GROUP BY sample_field -- grouping
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1 回答 1

2

好吧，这不清楚您想要做什么，因为没有条件可以将内部查询与外部查询相关联。我想这将是一个 store_id，如果是，你应该这样做：

SELECT sample_fields,-- some fields here
       results.department_occupancy_rate
FROM   sample_table -- a table here
       INNER JOIN sample_table1
               ON sample_table2 -- joining here
       JOIN (SELECT c.store_id,
                    c1 / c2 AS department_occupancy_rate
             -- doing division of results of both queries
             FROM   property AS c
                    JOIN (SELECT store_id,
                                 Cast(Count(*) AS DECIMAL(10, 2)) AS c1
                          FROM   property
                          WHERE  non_ha = 1
                                 AND property_type LIKE '%587%'
                          GROUP  BY store_id) AS sub1
                      ON c.store_id = sub1.store_id
                    JOIN (SELECT store_id,
                                 Cast(Count(*) AS DECIMAL(10, 2)) AS c2
                          FROM   property
                          WHERE  property_type LIKE '%587%'
                          GROUP  BY store_id) AS sub2
                      ON c.store_id = sub2.store_id) AS results
         ON ( sample_table.store_id = results.store_id )
GROUP  BY sample_field -- grouping
于 2012-09-14T16:09:35.323 回答