2

我有这个 SQL 查询。

SELECT
    c.id, 
    c.name,
    c.slug,
    sc.id,
    sc.name,
    sc.slug,
    COUNT(bsc.id) AS business_count
FROM
    fi_category c
LEFT JOIN
    fi_subcategory sc ON c.id = sc.category_id AND (sc.deleted_at IS NULL)
LEFT JOIN (
        fi_business b
    INNER JOIN
        fi_business_subcategory bsc ON b.id = bsc.business_id AND (bsc.deleted_at IS NULL)
    INNER JOIN
        fi_suburb su ON su.id = b.suburb_id AND su.city_id = 1
    ) ON sc.id = bsc.subcategory_id
WHERE 
    (c.deleted_at IS NULL) 
GROUP BY 
    c.id, sc.id

因为 DQL 不支持这种类型的查询。我想用它Doctrine_RawSql

我试过用这种方式。

$q = new Doctrine_RawSql();
$q->select('{c.name}, {c.slug}, {sc.name}, {sc.slug}, {COUNT(bsc.id) AS business_count}');
$q->from('fi_category c LEFT JOIN fi_subcategory sc ON c.id = sc.category_id AND (sc.deleted_at IS NULL) LEFT JOIN (fi_business b INNER JOIN fi_business_subcategory bsc ON b.id = bsc.business_id AND (bsc.deleted_at IS NULL) INNER JOIN fi_suburb su ON su.id = b.suburb_id AND su.city_id = 1) ON sc.id = bsc.subcategory_id');
$q->groupBy('GROUP BY c.id, sc.id');
$q->addComponent('c', 'Model_Category c');
$q->addComponent('sc', 'c.Subcategory sc');
$q->addComponent('bsc', 'sc.BusinessSubcategory bsc');
$q->addComponent('b', 'bsc.Business b');
$q->addComponent('su', 'b.Suburb su');
$q->execute();

此查询不起作用，这是Doctrine_Rawsql为上述 SQL 查询构建的正确方法吗？

如果有人想检查这里的表格是小提琴http://sqlfiddle.com/#!2/5adaa的链接

更新：这是这个问题的延续， 如果有人可以通过使用@MvG 提供的解决方案中的任何查询来帮助我构建，请根据条件选择查询和计数Doctrine_Rawsql

4

0 回答 0