sql - sql 从视图和表中选择

Question

我有一个选择查询，我想在其中对一个视图和另一个表进行连接。该视图工作正常，表格也可以单独工作。但是当我尝试做类似的事情时：

select VIEW.col1, VIEW.col2
from VIEW, TABLE
where VIEW.col1 = TABLE.col1

我明白了The multi-part identifier "VIEW.col1" could not be bound.

语法是错误的，还是视图中不允许这样做？

Answer 1

这应该工作

select v.col1, t.col2
from VIEW v, TABLE t
where v.col1 = t.col1

Answer 2

SELECT VIEW.col1, VIEW.col2
from VIEW AS VIEW INNER JOIN TABLE AS TABLE
ON VIEW.col1 = TABLE.col1

Answer 3

SELECT MYVIEWNAME.col1, MYVIEWNAME.col2
FROM VIEWNAME AS MYVIEWNAME INNER JOIN TABLENAME AS MYTABLENAME
ON MYVIEWNAME.col1 = MYTABLENAME.col1

Answer 4

我建议您使用左连接或内连接，并为表和视图设置别名。

select v.col1 , v.col2

 from view v
 inner join table t on t.col1 = v.col1

Answer 5

你必须有view这样的：

create table MyView
as
select column1 as col1, column2 as col2
from tab

or

CREATE VIEW MyView (col1,col2)
as
select column1, column2
from tab

然后你可以加入它：

select MyView.col1, MyView.col2
from MyView, TABLE
where MyView.col1 = MyView.col1

or

select v.col1, v.col2
from MyView v, TABLE t
where t.col1 = t.col1

or

select v.col1, v.col2
from MyView v
join TABLE t on t.col1 = t.col1

也许某些示例不适用于所有 RDBMS。