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如何拆分用于getline(cin, input);输入变量的输入字符串？我想将它拆分成一个 char 数组，如下所示：

char[] = { // What goes here to make it read the input variable and split it into chars }

有没有办法做到这一点？

你们的新帖子呢？哪个最好？这是我需要修改以读取输入变量并将其字符存储在字符数组中的凯撒密码：

// Test Code ONLY
// Not A Commercial Program OR A Crypter
// THIS IS A TEXT CIPHERER

#include <windows.h>
#include <cstdlib>
#include <iostream>
#include <string.h>
#include <vector>

using namespace std;

int main()

{
    string in;
    string out;
    char lower[25] = {a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z};
    char upper[25] = {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z};
    char upcip[25] = {Z,Y,X,W,V,U,T,S,R,Q,P,O,N,M,L,K,J,I,H,G,F,E,D,C,B,A};
    char locip[25] = {z,y,x,w,v,u,t,s,r,q,p,o,n,m,l,k,j,i,h,g,f,e,d,c,b,a};
    cout << "Enter PlainText: ";
    getline(cin, in);
    // which sample goes here to read the input var char by char, then store the chars in order in a char array in your opinion?
    return 0;
}
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2 回答 2

4

字符串已经是一个字符数组：

for (std::string line; std::getline(std::cin, line); )
{
    for (std::size_t i = 0, e = line.size(); i != e; ++i)
    {
        std::cout << "char[" << i << "] = '" << line[i] << "'\n";
    }
}
于 2012-09-13T12:28:43.867 回答
0 
string str;
    std::getline(cin,str);
    char* pArr = new char[str.size() + 1]; // add 1 for zero element which is the end of string
    strcpy(pArr,str.c_str());

/*
some actions with pArr, for ex.
while(*pArr)
    std::cout << *pArr; // output string on the screen

*/

// updated: release memory obtained from heap
delete [] pArr;
于 2012-09-13T12:32:21.937 回答