我需要问一些事情，但我被困住了：这是我的控制器代码：
public ActionResult FastRegister(FormCollection collection)
{
UserModel db = new UserModel(0);
string str = "";
//Boolean
//Common.IsAlphaNumeric_Dot_Underscore()? er
errorInsert err = new errorInsert();
try
{
db.set_value(0, Common.HtmlFormUrlEncode(collection["user_name"]), Common.HtmlFormUrlEncode(collection["user_pass"]), "", "", Common.HtmlFormUrlEncode(collection["user_email"]), "", DateTime.Now, "", Common.RandomString(false), 0);
db.Insert();
err.duplicate = false;
err.error = "success register";
return Json(err, JsonRequestBehavior.AllowGet);
}
catch (Exception exception)
{
if (exception.Message.Contains("unique") == true && exception.Message.Contains("duplicate") == true)
{
err.duplicate = true;
err.error = "username or email already taken";
}
else
{
err.duplicate = false;
err.error = exception.Message;
}
return Json(err, JsonRequestBehavior.AllowGet);
}
}
}
class errorInsert
{
public Boolean duplicate;
public string error;
public errorInsert()
{
}
}
这是我的jQuery代码：
<script type="text/javascript">
$(document).ready(function(){
function ajax_send_url(user_name, user_pass, user_email)
{
$.ajax({
type: 'POST',
url: 'http://localhost/smile/User/FastRegister',
data: 'user_name='+user_name+'&user_pass='+user_pass+'&user_email='+user_email,
//contentType: 'application/json; charset=utf-8',
success: function(e)
{
//var x=jQuery.parseJSON(e);
$("#loading").html(e.error);
}
, dataType:"json"
, beforeSend:function (e){$("#loading").html('<img src="loading.gif" width="50px">');}
});
}
$("#register").click
(
function()
{
var user_name = $("#user_name").val();
var user_pass = $("#user_pass").val();
var user_email = $("#user_email").val();
ajax_send_url(user_name,user_pass,user_email );
}
);
});
我有我的萤火虫 200 OK Http 但当我检查时没有响应。请有人弄清楚并帮助我。谢谢...