问问题
82 次
1 回答
9
Because you've entirely replaced the original prototype
object of f
with a plain object. It was the original prototype
object that held the reference to f
via the .constructor
property.
The constructor of an object created using object literal syntax will be the Object
constructor.
To get it back, you'd need to put it there manually.
f = function() {};
f.prototype = {};
f.prototype.constructor = f;
thing = new f;
This will shadow the .constructor
property on in the prototype chain of the new prototype object.
If you delete that property, you'll get Object
again.
delete f.prototype.constructor;
console.log(thing.constructor); // Object
于 2012-09-12T19:29:12.790 回答