5

下面是表数据（一小块），基本上我希望在按帐户编号分组时仅查询具有最小 original_date_ctr 的行。

我尝试过使用 HAVING(MIN()) 和 where = Min() 以及其他没有运气的方法。

这里的正确结果会给我 id_ctr 688、1204 和 1209

id_ctr  account_number_cus  original_date_ctr   mrc_ctr  
------  ------------------  -----------------  ----------
   688               20062  2008-05-17             138.97
  1204              151604  2006-08-10           42000.00
  1209              151609  2006-06-29             968.68
  1367               20062  2011-10-27             207.88
  1434              151609  2009-09-10            1469.62
  1524              151604  2009-09-01           36999.99
  1585              151609  2012-05-31            1683.88
4

2 回答 2

11

使用连接执行此操作会更快：

SELECT a.*
FROM mytable a
LEFT JOIN mytable b
  ON a.account_number_cus = b.account_number_cus
  AND b.original_date_ctr < a.original_date_ctr
WHERE b.id_ctr IS NULL
于 2012-09-11T21:38:55.487 回答
4

您可以通过以下方式执行此操作：

select t1.id_ctr,
    t1.account_number_cus,
    t1.original_date_ctr,
    t1.mrc_ctr  
from yourtable t1
inner join
(
    select min(original_date_ctr) as mindate, account_number_cus
    from yourtable
    group by account_number_cus
) t2
    on t1.account_number_cus = t2.account_number_cus
    and t1.original_date_ctr = t2.mindate

见SQL Fiddle with Demo

于 2012-09-11T21:33:16.673 回答