9

我需要链接两个 MapReduce 作业。我使用 JobControl 将 job2 设置为 job1 的依赖项。它工作，输出文件被创建！但它不会停止！在 shell 中，它保持这种状态：

12/09/11 19:06:24 WARN mapred.JobClient: Use GenericOptionsParser for parsing the arguments. Applications should implement Tool for the same.
12/09/11 19:06:25 INFO input.FileInputFormat: Total input paths to process : 1
12/09/11 19:06:25 INFO util.NativeCodeLoader: Loaded the native-hadoop library
12/09/11 19:06:25 WARN snappy.LoadSnappy: Snappy native library not loaded
12/09/11 19:07:00 WARN mapred.JobClient: Use GenericOptionsParser for parsing the arguments. Applications should implement Tool for the same.
12/09/11 19:07:00 INFO input.FileInputFormat: Total input paths to process : 1

我怎样才能阻止它？这是我的主要内容。

public static void main(String[] args) throws Exception {
    Configuration conf = new Configuration();
    Configuration conf2 = new Configuration();

    Job job1 = new Job(conf, "canzoni");
    job1.setJarByClass(CanzoniOrdinate.class);
    job1.setMapperClass(CanzoniMapper.class);
    job1.setReducerClass(CanzoniReducer.class);
    job1.setOutputKeyClass(Text.class);
    job1.setOutputValueClass(IntWritable.class);

    ControlledJob cJob1 = new ControlledJob(conf);
    cJob1.setJob(job1);
    FileInputFormat.addInputPath(job1, new Path(args[0]));
    FileOutputFormat.setOutputPath(job1, new Path("/user/hduser/tmp"));


    Job job2 = new Job(conf2, "songsort");
    job2.setJarByClass(CanzoniOrdinate.class);
    job2.setMapperClass(CanzoniSorterMapper.class);
    job2.setSortComparatorClass(ReverseOrder.class);
    job2.setInputFormatClass(KeyValueTextInputFormat.class);
    job2.setReducerClass(CanzoniSorterReducer.class);
    job2.setMapOutputKeyClass(IntWritable.class);
    job2.setMapOutputValueClass(Text.class);
    job2.setOutputKeyClass(Text.class);
    job2.setOutputValueClass(IntWritable.class);

    ControlledJob cJob2 = new ControlledJob(conf2);
    cJob2.setJob(job2);
    FileInputFormat.addInputPath(job2, new Path("/user/hduser/tmp/part*"));
    FileOutputFormat.setOutputPath(job2, new Path(args[1]));

    JobControl jobctrl = new JobControl("jobctrl");
    jobctrl.addJob(cJob1);
    jobctrl.addJob(cJob2);
    cJob2.addDependingJob(cJob1);
    jobctrl.run();


    ////////////////
    // NEW CODE ///   
    //////////////


    // delete jobctrl.run();
    Thread t = new Thread(jobctrl);
    t.start();
    String oldStatusJ1 = null;
    String oldStatusJ2 = null;
    while (!jobctrl.allFinished()) {
      String status =cJob1.toString();
      String status2 =cJob2.toString();
      if (!status.equals(oldStatusJ1)) {
        System.out.println(status);
        oldStatusJ1 = status;
      }
      if (!status2.equals(oldStatusJ2)) {
        System.out.println(status2);
        oldStatusJ2 = status2;
      }     
     }
    System.exit(0);

} }

4

4 回答 4

6

我基本上做了 Pietro 上面提到的事情。

public class JobRunner implements Runnable {
  private JobControl control;

  public JobRunner(JobControl _control) {
    this.control = _control;
  }

  public void run() {
    this.control.run();
  }
}

在我的 map/reduce 类中，我有：

public void handleRun(JobControl control) throws InterruptedException {
    JobRunner runner = new JobRunner(control);
    Thread t = new Thread(runner);
    t.start();

    while (!control.allFinished()) {
        System.out.println("Still running...");
        Thread.sleep(5000);
    }
}

我只是在其中传递了 jobControl 对象。

于 2013-06-28T15:44:22.880 回答
3

JobControl 对象本身是可运行的，因此您可以像这样使用它：

new Thread(myJobControlInstance).start()
于 2014-07-03T20:22:18.593 回答
0

只需对 sinemetu1 共享的代码片段进行调整即可。

您可以放弃对 JobRunner 的调用，因为 JobControl 本身实现了 Runnable

        Thread thread = new Thread(jobControl);
        thread.start();

        while (!jobControl.allFinished()) {
            System.out.println("Still running...");
            Thread.sleep(5000);
        }

我还偶然发现了这个链接，用户确认 JobControl 只能使用新线程运行。 https://www.mail-archive.com/common-user@hadoop.apache.org/msg00556.html

于 2015-03-17T17:21:40.893 回答
0

尝试这个：

    Thread jcThread = new Thread(jobControl);
    jcThread.start();
    System.out.println("循环判断jobControl运行状态 >>>>>>>>>>>>>>>>");
    while (true) {
        if (jobControl.allFinished()) {
        System.out.println("====>> jobControl.allFinished=" + jobControl.getSuccessfulJobList());
        jobControl.stop();
        // 如果不加 break 或者 return，程序会一直循环
        break;
    }

    if (jobControl.getFailedJobList().size() > 0) {
        succ = 0;
        System.out.println("====>> jobControl.getFailedJobList=" + jobControl.getFailedJobList());
        jobControl.stop();

        // 如果不加 break 或者 return，程序会一直循环
        break;
    }
}
于 2017-07-13T08:07:46.430 回答