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我有一个网络应用程序，它是一个游戏，只有在达到一定分数后，人们才能成为朋友，并且应该自动添加到彼此的好友列表中。

试图弄清楚如何像这样在 Ejabberd 中处理名册

  • 防止任何用户自行添加其他人
  • 只让 webapp 处理对名册的修改（buddylist）

使用像 strophe 这样的客户端 JS 库并不安全，我需要将用户添加到彼此名册的服务器端方法。关于如何使用 Ejabberd 做到这一点的任何想法？

编辑：好的，似乎 ejabberd 的 mod_rest 提供了对（全部？）ejabbard 方法的完全访问权限

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1 回答 1

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好的，所以在我走上正确的轨道后，我设法在一个小时内弄清楚了..

  • 安装 ejabberd
  • 安装 mod_rest
  • 安装 mod_admin_extra

命令：

ejabberdctl help process_rosteritems

：

Command Name: process_rosteritems

  Arguments: action::string
             subs::string
             asks::string
             users::string
             contacts::string

  Returns: res::rescode

  Tags: roster 

  Description: List or delete rosteritems that match filtering options 

Explanation of each argument:
 - action: what to do with each rosteritem that matches all the filtering options
 - subs: subscription type
 - asks: pending subscription
 - users: the JIDs of the local user
 - contacts: the JIDs of the contact in the roster

Allowed values in the arguments:
 ACTION = list | delete
 SUBS = SUB[:SUB]* | any
 SUB = none | from | to | both
 ASKS = ASK[:ASK]* | any
 ASK = none | out | in
 USERS = JID[:JID]* | any
 CONTACTS = JID[:JID]* | any
 JID = characters valid in a JID, and can use the globs: *, ?, ! and [...]

This example will list roster items with subscription 'none', 'from' or 'to' that have any ask property, of local users which JID is in the virtual host 'example.org' 
and that the contact JID is either a bare server name (without user part) or that has a user part and the server part contains the word 'icq':
 list none:from:to any *@example.org *:*@*icq*
于 2012-09-11T16:42:36.483 回答