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我想创建收音机播放器并在我回去时在后台播放然后播放收音机。我也想保持停止，暂停，下一个，上一个按钮。但是如何使用服务类在 Android 中播放、停止、暂停等。

有想法？？提前致谢...

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2 回答 2

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这是您可以尝试的示例...

创建一个 ServiceDemo.java 活动

 public class ServicesDemo extends Activity implements OnClickListener {
  private static final String TAG = "ServicesDemo";
  Button buttonStart, buttonStop;

  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    buttonStart = (Button) findViewById(R.id.buttonStart);
    buttonStop = (Button) findViewById(R.id.buttonStop);

    buttonStart.setOnClickListener(this);
    buttonStop.setOnClickListener(this);
  }

  public void onClick(View src) {
    switch (src.getId()) {
    case R.id.buttonStart:
      Log.d(TAG, "onClick: starting srvice");
      startService(new Intent(this, MyService.class));
      break;
    case R.id.buttonStop:
      Log.d(TAG, "onClick: stopping srvice");
      stopService(new Intent(this, MyService.class));
      break;
    }
  }
}

创建一个名为 MyService.java 的服务

public class MyService extends Service {
    private static final String TAG = "MyService";
    MediaPlayer player;

    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

    @Override
    public void onCreate() {
        Toast.makeText(this, "My Service Created", Toast.LENGTH_LONG).show();
        Log.d(TAG, "onCreate");

        player = MediaPlayer.create(this, R.raw.braincandy);
        player.setLooping(false); // Set looping
    }

    @Override
    public void onDestroy() {
        Toast.makeText(this, "My Service Stopped", Toast.LENGTH_LONG).show();
        Log.d(TAG, "onDestroy");
        player.stop();
    }

    @Override
    public void onStart(Intent intent, int startid) {
        Toast.makeText(this, "My Service Started", Toast.LENGTH_LONG).show();
        Log.d(TAG, "onStart");
        player.start();
    }
}

AndroidManifest.xml

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
  package="com.example" android:versionCode="1" android:versionName="1.0">
  <application android:icon="@drawable/icon" android:label="@string/app_name">
    <activity android:name=".ServicesDemo" android:label="@string/app_name">
      <intent-filter>
        <action android:name="android.intent.action.MAIN" />
        <category android:name="android.intent.category.LAUNCHER" />
      </intent-filter>
    </activity>
    <service android:enabled="true" android:name=".MyService" />
  </application>
  <uses-sdk android:minSdkVersion="3" />
</manifest>

主要的.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:gravity="center">
<TextView  
    android:layout_width="fill_parent" 
    android:layout_height="wrap_content" android:text="Services Demo" android:gravity="center" android:textSize="20sp" android:padding="20dp"/>
<Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/buttonStart" android:text="Start"></Button>
<Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Stop" android:id="@+id/buttonStop"></Button>
</LinearLayout>
于 2012-09-11T11:58:28.837 回答
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为此，您必须将服务与您的活动绑定。您可以按照以下链接将服务与活动绑定。 https://stackoverflow.com/a/10799514/630668

于 2012-09-11T11:47:23.540 回答