可能重复:
唯一的随机字符串生成
我必须生成一个随机的唯一字符串。这样做的目的是在表格中的每个成功条目后生成一个幸运数字。
我不喜欢使用 GUID,因为它在两者之间是破折号(-)。 这是一个例子,但它似乎也太长了。
我想生成一个大约 10 个字符的字符串。
任何好的想法将不胜感激。干杯
可能重复:
唯一的随机字符串生成
我必须生成一个随机的唯一字符串。这样做的目的是在表格中的每个成功条目后生成一个幸运数字。
我不喜欢使用 GUID,因为它在两者之间是破折号(-)。 这是一个例子,但它似乎也太长了。
我想生成一个大约 10 个字符的字符串。
任何好的想法将不胜感激。干杯
您可以创建不带破折号的 Guid 的字符串表示形式:
Guid.NewGuid().ToString("N");
当然,它有 32 个字符长,而不是 10 个字符。但它是一个简单而快速的解决方案。
你可以试试这个:
public struct ShortGuid
{
private Guid _underlyingGuid;
public ShortGuid(Guid underlyingGuid) : this()
{
_underlyingGuid = underlyingGuid;
}
public static ShortGuid Empty
{
get { return ConvertGuidToShortGuid(Guid.Empty); }
}
public static ShortGuid NewShortGuid()
{
return ConvertGuidToShortGuid(Guid.NewGuid());
}
private static ShortGuid ConvertGuidToShortGuid(Guid guid)
{
return new ShortGuid(guid);
}
public override string ToString()
{
return Convert.ToBase64String(_underlyingGuid.ToByteArray()).EscapeNonCharAndNonDigitSymbols();
}
public bool Equals(ShortGuid other)
{
return other._underlyingGuid.Equals(_underlyingGuid);
}
public override bool Equals(object obj)
{
if (ReferenceEquals(null, obj)) return false;
if (obj.GetType() != typeof (ShortGuid)) return false;
return Equals((ShortGuid) obj);
}
public override int GetHashCode()
{
return _underlyingGuid.GetHashCode();
}
}
其中EscapeNonCharAndNonDigitSymbols是一个扩展方法:
public static string EscapeNonCharAndNonDigitSymbols(this string str)
{
if (str == null)
throw new NullReferenceException();
var chars = new List<char>(str.ToCharArray());
for (int i = str.Length-1; i>=0; i--)
{
if (!Char.IsLetterOrDigit(chars[i]))
chars.RemoveAt(i);
}
return new String(chars.ToArray());
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Security.Cryptography;
namespace LinqRandomString
{
class Program
{
static void Main(string[] args)
{
do
{
byte[] random = new byte[10000];
using (var rng = RandomNumberGenerator.Create())
rng.GetBytes(random);
var q = random
.Where(i => (i >= 65 && i <= 90) || (i >= 97 && i <= 122)) // ascii ranges - change to include symbols etc
.Take(10) // first 10
.Select(i => Convert.ToChar(i)); // convert to a character
foreach (var c in q)
Console.Write(c);
} while (Console.ReadLine() != "exit");
}
}
}
就在昨天不得不做同样的任务。干得好:
public static class RandomStringService
{
//Generate new random every time used. Must sit outside of the function, as static, otherwise there would be no randomness.
private static readonly Random Rand = new Random((int)DateTime.Now.Ticks);
/// <summary>
/// Create random unique string- checking against a table
/// </summary>
/// <returns>Random string of defined length</returns>
public static String GenerateUniqueRandomString(int length)
{
//check if the string is unique in Barcode table.
String newCode;
do
{
newCode = GenerateRandomString(length);
// and check if there is no duplicates, regenerate the code again.
} while (_tableRepository.AllRecords.Any(l => l.UniqueString == newCode));
//In my case _tableRepository is injected via DI container and represents a proxy for
//EntityFramework context. This step is not really necessary, most of the times you can use
//method below: GenerateRandomString
return newCode;
}
/// <summary>
/// Generates the random string of given length.
/// String consists of uppercase letters only.
/// </summary>
/// <param name="size">The required length of the string.</param>
/// <returns>String</returns>
private static string GenerateRandomString(int size)
{
StringBuilder builder = new StringBuilder();
char ch;
for (int i = 0; i < size; i++)
{
ch = Convert.ToChar(CreateRandomIntForString());
builder.Append(ch);
}
return builder.ToString();
}
/// <summary>
/// Create a random number corresponding to ASCII uppercase or a digit
/// </summary>
/// <returns>Integer between 48-57 or between 65-90</returns>
private static int CreateRandomIntForString()
{
//ASCII codes
//48-57 = digits
//65-90 = Uppercase letters
//97-122 = lowercase letters
int i;
do
{
i = Convert.ToInt32(Rand.Next(48, 90));
} while (i > 57 && i < 65);
return i;
}