ios - 如何分离其他东西的字符串值？

Question

 UIAlertView *myAlert=[[UIAlertView alloc]
initWithTitle:@"Logging in" message:@"you are a member in our website \nWelcome Dear  %@ ",UserName.text
            delegate:self
            cancelButtonTitle:@"Done"
            otherButtonTitles:nil];

这段代码对我显示错误，因为我输入了字符串变量，它是一个名为“用户名”的文本字段的文本

那我怎么能把这条线分开呢？

initWithTitle:@"Logging in" message:@"you are a member in our website \nWelcome Dear %@ ",UserName.text delegate:self

因为错误在这里显示在delegate HELP这个词中

Answer 1

使用以下格式：

UIAlertView *myAlert=[[UIAlertView alloc]
initWithTitle:@"Logging in" message:[NSString stringWithFormat:@"you are a member in our website \nWelcome Dear  %@ ",UserName.text]
            delegate:self
            cancelButtonTitle:@"Done"
            otherButtonTitles:nil];

Answer 2

试试这个：

NSString *alertstr=[NSString stringWithFormat:@"you are a member in our website \nWelcome Dear  %@",UserName.text];
UIAlertView *myAlert=[[UIAlertView alloc]
                          initWithTitle:@"Logging in" message:alertstr
                          delegate:self
                          cancelButtonTitle:@"Done"
                          otherButtonTitles:nil];

Answer 3

重组它如下：

NSString *psMsg = [NSString stringFromFormat: @"you are a member in our website \nWelcome Dear  %@ ", UserName.text, nil];
UIAlertView *myAlert=[[UIAlertView alloc]
    initWithTitle:@"Logging in" message:psMsg
    delegate:self cancelButtonTitle:@"Done"
    otherButtonTitles:nil];

分解事物，以便更容易调试和理解正在发生的事情。

Answer 4

这是因为您没有创建字符串作为参数。

您可以通过在行中声明您的字符串（选项 1）或将字符串创建移到 UIAlert 视图之外（选项 2）来解决此问题。

我喜欢对所有字符串使用本地化字符串（选项 3），因为它有助于从代码中获取字符串，允许字符串重用并有助于国际化。

选项1：

UIAlertView *myAlert=[[UIAlertView alloc]
                        initWithTitle:@"Logging in" 
                        message:[NSString stringWithFormat:@"you are a member in our website \nWelcome Dear  %@ ",UserName.text]
                        delegate:self
                        cancelButtonTitle:@"Done"
                        otherButtonTitles:nil];

选项 2：

NSString *alertstr=[NSString stringWithFormat:@"you are a member in our website \nWelcome Dear  %@",UserName.text];

UIAlertView *myAlert=[[UIAlertView alloc]
                          initWithTitle:@"Logging in" message:alertstr
                          delegate:self
                          cancelButtonTitle:@"Done"
                          otherButtonTitles:nil];

选项 3：

UIAlertView *myAlert=[[UIAlertView alloc]
                        initWithTitle:NSLocalizedString(@"Login-title", nil) 
                        message:NSLocalizedString(@"Login-message",nil)
                        delegate:self
                        cancelButtonTitle:NSLocalizedString(@"Done", nil)
                        otherButtonTitles:nil];

Answer 5

我认为这是唯一的方法，当您显示该消息时无需显示登录。

UIAlertView *myAlert=[[UIAlertView alloc]initWithTitle:@"you are a member in our website Welcome Dear " message:mytext.text
                      delegate:self
                      cancelButtonTitle:@"Done"
                      otherButtonTitles:nil];

[myAlert show];
[myAlert release];