我在代码的输出中看到了一个我不理解的奇怪之处。我在头文件中定义了一个结构。我在用户空间中填充一个结构,然后通过 ioctl 将其发送到内核模块。内核模块应该从用户那里复制它,然后报告用户存储的值。
结构定义为:
typedef struct Command_par {
int cmd; /**< special driver command */
int target; /**< special configuration target */
unsigned long val1; /**< 1. parameter for the target */
unsigned long val2; /**< 2. parameter for the target */
int error; /**< return value */
unsigned long retval; /**< return value */
} Command_par_t ;
用户空间代码只是一个快速测试程序:
#include <stdio.h>
#include <errno.h>
#include <string.h>
#include <fcntl.h>
#include <sys/stat.h>
#include "can4linux.h" //can4linux is the standard can driver that comes
//with the uCLinux kernel (where this code was originally
//running before this port to a desktop machine
#define CAN_COMMAND 0
void main()
{
long ret;
Command_par_t cmd;
int fd;
//set and open the file descriptor to the device
cmd.cmd = 2;
cmd.target = 9;
cmd.val1 = 8;
cmd.val2 = 7;
cmd.error = 6;
cmd.retval = 5;
ret = ioctl(fd, CAN_COMMAND, &cmd);
通过 ioctl 获取打开/发送数据的内核模块:
long can_ioctl(struct file *file, unsigned int cmd, unsigned long arg)
{
Command_par_t *myptr;
myptr = (void *)kmalloc(sizeof(Command_par_t)+1,GFP_KERNEL );
copy_from_user((void *)myptr, (void *)arg, sizeof(Command_par_t));
printk("cmd = %d, target = %d, val1 = %d, val2 = %d, error = %d, retval = %d\n",
myptr->cmd, myptr->target, myptr->val1, myptr->val2, myptr->error, myptr->retval);
这是在 can4linux.h 头文件中定义可能的 IOCTL 命令的地方:
---------- IOCTL requests */
#define COMMAND 0 /**< IOCTL command request */
#define CONFIG 1 /**< IOCTL configuration request */
#define SEND 2 /**< IOCTL request */
#define RECEIVE 3 /**< IOCTL request */
#define CONFIGURERTR 4 /**< IOCTL request */
所以显然这只是测试代码,我正在尝试调试一个更大的问题,但现在即使这也不能正常工作......我得到的输出是:
[217088.860190] cmd = 2, target = 1, val1 = 3, val2 = 134514688, error = 134514480, retval = 0
cmd 设置正确,之后其他所有内容都被扭曲了......看起来它只传递了一个 int 然后我正在访问我的结构之外的内存?有人看到我在这里做错了吗?