我对以下代码中的查询没有任何问题。但是第二个代码抛出了错误
您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，以在第 1 行的 '' 附近使用正确的语法
工作代码：
<?php
mysql_connect("localhost", "","") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
$result =" CREATE TABLE google_csv(
ÿþName varchar(80),
Given_Name varchar(80),
Additional_Name varchar(80),
Family_Name varchar(80),
Yomi_Name varchar(80),
Given_Name_Yomi varchar(80),
Additional_Name_Yomi varchar(80),
Family_Name_Yomi varchar(80),
Name_Prefix varchar(80),
Name_Suffix varchar(80),
Initials varchar(80),
Nickname varchar(80),
Short_Name varchar(80),
Maiden_Name varchar(80),
Birthday varchar(80),
Gender varchar(80),
Location varchar(80),
Billing_Information varchar(80),
Directory_Server varchar(80),
Mileage varchar(80),
Occupation varchar(80),
Hobby varchar(80),
Sensitivity varchar(80),
Priority varchar(80),
Subject varchar(80),
Notes varchar(80),
Group_Membership varchar(80),
E_mail_1___Type int(11),
E_mail_1___Value int(11),
E_mail_2___Type int(11),
E_mail_2___Value int(11),
Phone_1___Type int(11),
Phone_1___Value int(11),
Phone_2___Type int(11),
Phone_2___Value int(11),
Phone_3___Type int(11),
Phone_3___Value int(11),
Address_1___Type int(11),
Address_1___Formatted int(11),
Address_1___Street int(11),
Address_1___City int(11),
Address_1___PO_Box int(11),
Address_1___Region int(11),
Address_1___Postal_Code int(11),
Address_1___Country int(11),
Address_1___Extended_Address int(11),
Website_1___Type int(11),
Website_1___Value int(11)
)";
echo $result;
mysql_query($result);
echo mysql_error();
?>
错误生成代码；
<?php
// GENERATE TABLE FROM FIRST LINE OF CSV FILE
$inputFile = 'google.csv';
$tableName = 'google_csv';
$fh = fopen($inputFile, 'r');
$contents = fread($fh, 5120); // 5KB
fclose($fh);
$fileLines = explode("\n", $contents);
$fieldList = explode(',', $fileLines[0]);
$lastField=count($fieldList)-1;
echo "Total Fields :".count($fieldList)."<br>";
echo "Last Field :".$lastField."<br>";
$result ="CREATE TABLE $tableName(";
for($i = 0; $i < count($fieldList); $i++)
{
if(preg_match('/[1-9]/', $fieldList[$i]))
{
if ($i==$lastField)
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' int(11)';}
else
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' int(11),';}
}
else
{
if($i==$lastField)
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' varchar(80)';}
else
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' varchar(80),';}
}
}
$result .=")";
if ($result) {echo $result."<br>".$i."<br>";} else {Echo "Some Problem!";}
mysql_connect("localhost", "","") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
mysql_query($result);
echo mysql_error();
?>
我$result在第一个代码中使用了这里的输出，它工作得很好！我在第二个代码中哪里出错了？
$result 回显给出
创建表 google_csv(ÿþName varchar(80),Given_Name varchar(80),Additional_Name varchar(80),Family_Name varchar(80),Yomi_Name varchar(80),Given_Name_Yomi varchar(80),Additional_Name_Yomi varchar(80),Family_Name_Yomi varchar(80) ),Name_Prefix varchar(80),Name_Suffix varchar(80),Initials varchar(80),Nickname varchar(80),Short_Name varchar(80),Maiden_Name varchar(80),Birthday varchar(80),Gender varchar(80), Location varchar(80),Billing_Information varchar(80),Directory_Server varchar(80),Mileage varchar(80),Occupation varchar(80),Hobby varchar(80),Sensitivity varchar(80),Priority varchar(80),Subject varchar (80),Notes varchar(80),Group_Membership varchar(80),E_mail_1_type int(11),E_mail_1_Value int(11),E_mail_2_Type int(11), E_mail_2_Value int(11),Phone_1_Type int(11) ,电话_1_Value int(11),Phone_2_ Type int(11),Phone_2 _Value int(11),Phone_3_ Type int(11),Phone_3 _Value int(11),Address_1_ Type int(11),Address_1 _Formatted int(11),Address_1_ Street int(11),Address_1 _City int(11),Address_1_ PO_Box int(11),Address_1 _Region int(11),Address_1_ Postal_Code int(11),Address_1 _Country int(11),Address_1_ Extended_Address int(11),Website_1 _Type int (11),Website_1___值 int(11))
看起来这里一切都很好！但是之后......