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我正在编写一个简单的小脚本，以便在 Ultra 音乐节早鸟票开始销售时向我发送一条短信，以便我抢购它们。当我开始写这篇文章时，我认为 python 将是实现我目标的一种快速方法。我所做的是收集链接，然后对它们进行计数并确定是否有变化并将谷歌语音短信发送到几个号码。这是我针对 stackoverflow 运行的代码。

from googlevoice import Voice
from googlevoice.util import input
from bs4 import BeautifulSoup, SoupStrainer
from time import sleep
import urllib2
from array import *

#define login details
email = 'example@gmail.com'
password = 'password'
url = 'http://stackoverflow.com/questions'

def send_message(var_text):
    voice = Voice()
    voice.login(email, password)

    phoneNumber = array('L',[9998675309, 9998675309])   
    for i in phoneNumber:
        voice.send_sms(i, var_text)

#init
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))

link_count = len(soup)

#start the loop
var = 1
while var == 1 :  # This constructs an infinite loop
    soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
    if link_count != len(soup): 
        string = str('Link Count Changed\n\nSite:\n' + url + '\nPrev:\n' + str(link_count) + '\nNew:\n' + str(len(soup)))
        send_message(string)
        print (string)
        link_count = len(soup)
        sleep(10)
        pass
    else:
        print('Number of links ('+ str(link_count) + ') has not changed, going to sleep now.') 
        sleep(10)
        pass
print "Good bye!"

这是我不断收到的错误（似乎只在发送到多个号码时发生） 

doesn't work array('L',[9998675309, 9998675309])
works array('L',[9998675309])

错误：

bash-3.2# python gvsendalert.py 
Number of links (195) has not changed, going to sleep now.
Traceback (most recent call last):
  File "gvsendalert.py", line 32, in <module>
    send_message(string)
  File "gvsendalert.py", line 19, in send_message
    voice.send_sms(i, var_text)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/voice.py", line 151, in send_sms
    self.__validate_special_page('sms', {'phoneNumber': phoneNumber, 'text': text})
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/voice.py", line 225, in __validate_special_page
    load_and_validate(self.__do_special_page(page, data))
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/util.py", line 65, in load_and_validate
    validate_response(loads(response.read()))
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlevoice/util.py", line 59, in validate_response
    raise ValidationError('There was a problem with GV: %s' % response)
googlevoice.util.ValidationError: There was a problem with GV: {u'data': {u'code': 58}, u'ok': False}

好的，我已经考虑了你们中的一些人发布的内容并提出了这个问题。对于发送我的谷歌语音号码两次的号码数组，它将发送 2 条消息。如果我把我的朋友号码放在第二个它会打破它。这可能是因为我的朋友号码不是谷歌语音号码吗？我已经能够使用 Google Voice 和其他一些第 3 方 iPhone 应用程序向这个号码发送消息，所以我认为 python 模块会以相同的方式工作。

这是我的第二次修订代码：

def send_message(var_text):
    voice = Voice()
    voice.login(email, password)

    phoneNumber = ['myrealgooglenumber', 'myfriendsactualphonenumber']  
    for i in phoneNumber:
        print( str('sending to: ') + str(i))
        voice.send_sms(str(i), str(var_text))
        sleep(5)

#init
soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))

link_count = len(soup)

#start the loop
var = 1
while var == 1 :  # This constructs an infinite loop
    soup = BeautifulSoup(urllib2.urlopen(url).read(), parse_only=SoupStrainer('a'))
    if link_count != len(soup): 
        string = ('Link Count Changed\n\nSite:\n{0}\nPrev:\n{1}\nNew:\n{2}').format(url, link_count, len(soup))     
        send_message(string)        
        link_count = len(soup)
        print (string)
        sleep(10)
        pass
    else:
        string = ('Number of links ({0}) has not changed, going to sleep now.').format(str(link_count))
        print(string) 
        sleep(10)
        pass
print "Good bye!"

已经用 2 个谷歌语音号码进行了测试，并且可以正常工作。仍然不适用于非谷歌语音号码。

4

2 回答 2

0

Google 可能有一个计时器来防止您背靠背发送过多的 SMS 消息。

也许您可以尝试将循环更改为：

for i in phoneNumber:
    voice.send_sms(i, var_text)
    sleep(5)

另一种想法是，如果您使用 2 个不同的电话号码会更好吗？

于 2012-09-09T22:00:55.353 回答
0

看起来您正在使用整数作为电话号码。

电话号码不是真实的数字。

尝试使用字符串：

phoneNumber = ['9998675309', '9998675309']

此外，在样式说明中，请查看字符串格式：

string = 'Link Count Changed\n\nSite:\n{0}\nPrev:\n{1}\nNew:\n{2}').format(url, link_count, len(soup))
于 2012-09-09T22:10:04.803 回答