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我使用二维数组创建了一个包含 10x10 按钮的网格。我试过 x.getSource().getLabel() 但编译器说它们不兼容。我也想获得被点击的特定按钮。

我想获取从我制作的网格中单击的确切按钮并获取其标签。我需要使用什么方法？

import javax.swing.JFrame; //imports JFrame library
import javax.swing.JButton; //imports JButton library
import java.awt.GridLayout; //imports GridLayout library
import javax.swing.*;
import java.awt.event.*;
import java.util.*;

public class ButtonGrid extends JFrame implements ActionListener
{
    JFrame frame=new JFrame(); //creates frame
    JButton[][] grid; //names the grid of buttons
    public int x;
    public int y;
    public ButtonGrid(int width, int length)
    { //constructor
        char temp;
        String charput;
        frame.setLayout(new GridLayout(width,length)); //set layout
        grid = new JButton[width][length]; //allocate the size of grid
        for(int y=0; y<length; y++)
        { //start
            for(int x=0; x<width; x++) 
            {
                temp=charRand(); //get random character
                charput = ""+temp; //converts character to string
                grid[x][y]=new JButton(); //creates new button
                frame.add(grid[x][y]); //adds button to grid
                grid[x][y].addActionListener(this);
                grid[x][y].setLabel(charput); //set charput as label
            }
        }
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.pack(); //sets appropriate size for frame
        frame.setVisible(true); //makes frame visible
    }
    /* generates  randomiz letter for the button of the grid*/
    public char charRand()
    {
        String consonantList = new String("BCDFGHL"); //list 1
        String consonantList2 = new String("MNPRSTWY"); //list 2
        String consonantList3= new String("JQXZVK"); //list 3
        String vowelList = new String("AEIOU"); //list of vowels
        int vowelOrConsonant; //holder of random number 
        int chosen; //selects the chosen random letter
        Random randGen = new Random(); //generates random int value
        char selected; //gets the random letter chosen by variable chosen

        vowelOrConsonant = randGen.nextInt(4);
        if (vowelOrConsonant == 0)
        {
            chosen = randGen.nextInt(5); //list of vowels
            selected = vowelList.charAt(chosen); //selects a char from vowels
        }
        else if(vowelOrConsonant == 1)
        {
            chosen = randGen.nextInt(7); //list 1
            selected = consonantList2.charAt(chosen); //selects a char
        }
        else if(vowelOrConsonant == 2)
        {
            chosen = randGen.nextInt(8); //list 2
            selected = consonantList2.charAt(chosen); //selects a char
        }
        else
        {
            chosen = randGen.nextInt(6); //list 3
            selected = consonantList.charAt(chosen);
        }
        return selected; //returns the random letter
    }

    public static void main(String[] args) 
    {
        new ButtonGrid(10,10);//makes new ButtonGrid with 2 parameters
    }

    public void actionPerformed(ActionEvent x)
    {
        /* i get wrong output on this line. 
         * i want to get the exact button that was clicked and get its label.
         */ 
        if (x.getSource()==grid[x][y])
            JOptionPane.showMessageDialog(null,x.getSource().getLabel);
    }
}
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2 回答 2

0

getSource()返回 an Object，因此您需要将其转换为JButton，如下所示： 

public void actionPerformed(ActionEvent x) {
    JOptionPane.showMessageDialog(null, ((JButton)x.getSource()).getText());
}

另请注意，getLabel()andsetLabel()已弃用，应替换为getText()and setText()。

于 2012-09-09T11:21:29.997 回答
0

您可以创建一个扩展 Jbutton 的类。并向其中添加两个 int(X & Y) 类型的字段。构造函数将如下所示： public MyButton(int x, y);

当你填充你的网格时，不要直接使用 Jbutton 类。使用您的类并为 X 和 Y 提供您正在使用的周期的两个 i 和 j 参数。现在，当您为按钮使用 Action Listener 时，您可以使用他的 X 和 Y 字段，因为它们代表了它在网格上的位置。希望这可以帮助！它完全对我有用，而且非常简单。

于 2016-11-25T18:37:49.387 回答