在解密从 Android 应用程序发送的字符串时,我遇到了一个问题。只要写入非特殊字符(例如æ、ø、å),它就可以正常工作。如果我添加其中之一,它们将显示为“?”。
以下是字符串的加密方式(Java):
/*Constructor*/
public DataCrypt()
{
ivspec = new IvParameterSpec(iv.getBytes());
keyspec = new SecretKeySpec(SecretKey.getBytes(), "AES");
try
{
cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
}
catch (NoSuchAlgorithmException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (NoSuchPaddingException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public byte[] encrypt(String text) throws Exception
{
if(text == null || text.length() == 0)
throw new Exception("Empty string");
byte[] encrypted = null;
try
{
cipher.init(Cipher.ENCRYPT_MODE, keyspec, ivspec);
encrypted = cipher.doFinal(text.getBytes("UTF-8"));
}
catch (Exception e)
{
throw new Exception("[encrypt] " + e.getMessage());
}
return encrypted;
}
以下是字符串的解密方式:
function decrypt($code)
{
$code = $this->hex2bin($code);
$iv = $this->iv;
$td = mcrypt_module_open('rijndael-128', '', 'cbc', $iv);
mcrypt_generic_init($td, $this->key, $iv);
$decrypted = mdecrypt_generic($td, $code);
mcrypt_generic_deinit($td);
mcrypt_module_close($td);
return utf8_decode(trim($decrypted));
}
protected function hex2bin($hexdata)
{
$bindata = '';
for ($i = 0; $i < strlen($hexdata); $i += 2)
{
$bindata .= chr(hexdec(substr($hexdata, $i, 2)));
}
return $bindata;
}
function pkcs5_unpad($text)
{
$pad = ord($text{strlen($text)-1});
if ($pad > strlen($text))
return false;
if (strspn($text, chr($pad), strlen($text) - $pad) != $pad)
return false;
return substr($text, 0, -1 * $pad);
}
$Username = pkcs5_unpad($crypto->decrypt($Username)); //$crypto is an instance of the cryptography class which holds the methods.
echo $Username.'<br/>'; /*Print ??? for special characters like æ, ø, å*/
希望有人对我如何解决这个问题有一个想法,所以也可以写 ø æ å 。
谢谢你的帮助!