3

我对 SQL Server 还很陌生，仍在学习一些交易技巧，而另一个教我的人一周没有工作，通常我会先运行他的语句，然后运行它。

我要做的是删除此 select 语句中返回的所有内容：

SELECT * from LOCATIONS a Join CONTACTS b on a.location_ID = b.Location_ID 
join CONTACTS_SOURCES c on b.contact_ID = c.Contact_ID  where c.Source_ID = 10014918

我需要删除此语句从 CONTACTS 表和 LOCATIONS 表返回的内容。这样做时，哪条路线是最好的路线？

路线A：

delete from LOCATIONS a
Join CONTACTS b
on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c
on b.contact_ID = c.Contact_ID  where c.Source_ID = 10014918

或路线 B。

DELETE from LOCATIONS where (SELECT * from LOCATIONS a
Join CONTACTS b
on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c
on b.contact_ID = c.Contact_ID  where c.Source_ID = 10014918)

DELETE FROM CONTACTS where (SELECT * from LOCATIONS a
Join CONTACTS b
on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c
on b.contact_ID = c.Contact_ID  where c.Source_ID = 10014918)

我感觉 Route A. 不会从 LOCATIONS 和 CONTACTS 表中删除。

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2 回答 2

7

您的感觉是对的：DELETE 查询（实际上是任何 DML 查询）只能影响单个表。Route B 的问题是第二个查询不起作用，因为第一个查询删除了所有可能成为连接候选的行。

怎么样：

SELECT l.Location_ID, c.Contact_ID
  INTO #x
  FROM dbo.LOCATIONS AS l
  INNER JOIN dbo.CONTACTS AS c
  ON l.location_ID = c.Location_ID
  INNER JOIN dbo.CONTACTS_SOURCES AS cs
  ON c.contact_ID = cs.Contact_ID 
  WHERE cs.Source_ID = 10014918;

DELETE dbo.CONTACTS_SOURCES WHERE Contact_ID IN (SELECT Contact_ID FROM #x);

DELETE dbo.CONTACTS WHERE Contact_ID IN (SELECT Contact_ID FROM #x);

DELETE dbo.LOCATIONS WHERE Location_ID IN (SELECT Location_ID FROM #x);
于 2012-09-06T19:20:24.573 回答
1

如果您在所有 3 个表（联系人、位置和联系人来源）上都具有参照完整性，那么您需要按顺序从叶删除到父表：

  1. 联系方式_来源
  2. 联系人
  3. 地点
于 2012-09-06T19:23:14.710 回答