我是 C 新手,使用 Zed Shaw 的 Learn C the Hard Way 进行学习。我在找出为什么会出现以下内存错误时遇到了一些麻烦。我很确定我没有泄漏内存,因为我使用 Valgrind 检查我的代码。
以下是我的代码有问题的行:
: int main(int argc,char *argv[]){
if (argc<3) die ("USAGE : ex17 <dbfile> <action> [action params]");
...char *filename=argv[1];// how are we able to get away with one dimension?
char action =argv[2][0];
/*Line 166*/:struct Connection *conn=Database_open(filename,action);// error throwing line
函数 Database_open 定义为:
/*Line 61*/:struct Connection *Database_open(const char *filename, char mode)
{
/* data */
struct Connection *conn= malloc(sizeof(struct Connection));
if(!conn->db) die("Memory Error");//?
if(mode=='c'){
conn->file=fopen(filename,"w");
}
else{
conn->file=fopen(filename,"r+");
if(conn->file){
Database_load(conn);
}
}
if(!conn->file) die("Failed to open file");
return conn;
};
这是我使用的 die 函数:
void die (const char *message)
{
if(errno){
perror(message);
}
else{
printf("ERROR :%s\n", message);
}
exit(1);
}
当我使用 Valgrind 运行代码时,我得到:
==6112== Command: ./ex17 db.dat c
==6112==
==6112== Conditional jump or move depends on uninitialised value(s)
==6112== at 0x80487B3: Database_open (ex17.c:61)//Marked above
==6112== by 0x8048BAA: main (ex17.c:166)// Line numbers marked above
==6112==
ERROR :Memory Error
==6112==
==6112== HEAP SUMMARY:
==6112== in use at exit: 8 bytes in 1 blocks
==6112== total heap usage: 1 allocs, 0 frees, 8 bytes allocated
==6112==
==6112== LEAK SUMMARY:
==6112== definitely lost: 0 bytes in 0 blocks
==6112== indirectly lost: 0 bytes in 0 blocks
==6112== possibly lost: 0 bytes in 0 blocks
==6112== still reachable: 8 bytes in 1 blocks
==6112== suppressed: 0 bytes in 0 blocks
==6112== Rerun with --leak-check=full to see details of leaked memory
==6112==
==6112== For counts of detected and suppressed errors, rerun with: -v
==6112== Use --track-origins=yes to see where uninitialised values come from
==6112== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 0 from 0)
编辑
结构连接
struct Connection
{
/* data */
FILE *file;
struct Database *db;
};