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您好,我收到以下消息:

 <soapenv:Envelope xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope">
      <soapenv:Header>
         <wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" soapenv:mustUnderstand="true">
            <wsu:Timestamp xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="Timestamp-11">
               <wsu:Created>2012-09-06T09:59:04.031Z</wsu:Created>
               <wsu:Expires>2012-09-06T10:04:04.031Z</wsu:Expires>
            </wsu:Timestamp>
            <wsse:UsernameToken xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="UsernameToken-12">
               <wsse:Username>admin</wsse:Username>
               <wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">admin</wsse:Password>
            </wsse:UsernameToken>
         </wsse:Security>
      </soapenv:Header>
      <soapenv:Body />
   </soapenv:Envelope>

我想使用 XPath<wsse:Username>admin</wsse:Username>从传入消息中获取用户名

有什么建议吗?

编辑:

我试过这个:

<inSequence xmlns="http://ws.apache.org/ns/synapse">
   <property xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" name="p1" expression="$header/wsse:Username" scope="default" />
   <log>
      <property name="output*********" expression="get-property('p1')" />
   </log>
</inSequence>

但它不输出用户名:

MessageID: urn:uuid:68f95493-7dfd-416a-b
455-f77f4fd5c9c5, Direction: request, output********* =
4

2 回答 2

1

努维奥,

您可以使用表达式“$header/wsse:Security”,其中“wsse”作为 Security 标头元素携带的命名空间的前缀。下面显示了如何将其保存到 Synapse 消息上下文属性。

<property xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" name="Security" expression="$header/wsse:Security" />

仅供参考,您可以使用语法“$header/header_name”来提取 SOAP 消息中存在的任何 SOAP 标头元素。

希望这可以帮助!

干杯,普拉巴斯

于 2012-09-08T04:05:14.340 回答
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否则你可以选择让它使用这个xpath:"//wsse:Username/text()" 我认为它会帮助你我也是这个wso2工具的新手。

希望这能带你..

于 2013-01-24T06:52:45.417 回答