0

我有一个多维数组。格式如下：

Array
(
    [1] => 2012.09.04;01:00;NZD;ANZ Commodity Price;1;0.5%;;-0.5%;1346720400
    [2] => 2012.09.04;01:30;AUD;Current Account Balance;2;-11.80B;-12.2B;-14.90B;1346722200
    [3] => 2012.09.04;01:30;JPY;Labor Cash Earnings (YoY);2;-1.2%;-0.3%;-0.6%;1346722200
    [4] => 2012.09.04;04:30;AUD;RBA Interest Rate Decision;3;3.5%;3.5%;3.5%;1346733000
    [5] => 2012.09.04;05:45;CHF;Gross Domestic Product (YoY);3;0.5%;1.6%;2.0%;1346737500
)

现在我使用这个函数转换它：

private function array_to_json($array) {    

    $arr_out = array();
    foreach ($array as &$r) {
       $arr_out[] = explode(";", $r);
    }
    unset($r);
    return $arr_out;
}

并得到这个结果：

Array
(
    [0] => Array
        (
            [0] => 2012.09.04
            [1] => 01:00
            [2] => NZD
            [3] => ANZ Commodity Price
            [4] => 1
            [5] => 0.5%
            [6] => 
            [7] => -0.5%
            [8] => 1346720400
        )

    [1] => Array
        (
            [0] => 2012.09.04
            [1] => 01:30
            [2] => AUD
            [3] => Current Account Balance
            [4] => 2
            [5] => -11.80B
            [6] => -12.2B
            [7] => -14.90B
            [8] => 1346722200
        )

    [2] => Array
        (
            [0] => 2012.09.04
            [1] => 01:30
            [2] => JPY
            [3] => Labor Cash Earnings (YoY)
            [4] => 2
            [5] => -1.2%
            [6] => -0.3%
            [7] => -0.6%
            [8] => 1346722200
        )

    [3] => Array
        (
            [0] => 2012.09.04
            [1] => 04:30
            [2] => AUD
            [3] => RBA Interest Rate Decision
            [4] => 3
            [5] => 3.5%
            [6] => 3.5%
            [7] => 3.5%
            [8] => 1346733000
        )

    [4] => Array
        (
            [0] => 2012.09.04
            [1] => 05:45
            [2] => CHF
            [3] => Gross Domestic Product (YoY)
            [4] => 3
            [5] => 0.5%
            [6] => 1.6%
            [7] => 2.0%
            [8] => 1346737500
        )

    [5] => Array
        (
            [0] => 2012.09.04
            [1] => 05:45
            [2] => CHF
            [3] => Gross Domestic Product s.a. (QoQ)
            [4] => 2
            [5] => -0.1%
            [6] => 0.2%
            [7] => 0.7%
            [8] => 1346737500
        )
)

其中 [8] 是时间戳。

如何找到第一个即将发生的事件 ([8]>time()) 并返回它的值？谢谢！

4

2 回答 2

1

您必须检查所有 [8] 个项目，并检查每个项目是否大于 time()。如果是这样，则将它们组成一个数组。最后，在这个数组上使用一个min 函数来获得最小的数字。

代码：

$future = array();
foreach($arr_out as $a)
    if ($a[8] > time())
        $future[] = $a[8];

$nearest = min($future); //contains the first upcoming event
于 2012-09-06T08:03:20.403 回答
0

试试这个：-

$marr = array
(
   array
        (
            '0' => '2012.09.04',
            '1' => '01:30',
            '2' => 'AUD',
            '3' => 'Current Account Balance',
            '4' => 2,
            '5' => '-11.80B',
            '6' => '-12.2B',
            '7' => '-14.90B',
            '8' => 1346919271,
        ),array
        (
            '0' => '2012.09.04',
            '1' => '01:30',
            '2' => 'AUD',
            '3' => 'Current Account Balance',
            '4' => 2,
            '5' => '-11.80B',
            '6' => '-12.2B',
            '7' => '-14.90B',
            '8' => 1346919686,
        )
);

$upComingArray = '';
foreach($marr as $key)
{
    $end =  end($key);
    if ($end > time()){

        $upComingArray[] = $key;
    }
}
echo "<pre>";
print_r($upComingArray);
于 2012-09-06T08:22:53.080 回答