编写 C/C++/Java 代码将给定的数字转换为单词。
例如：- 输入：1234
输出：一千二百三十四。
输入：10
输出：十
它是否需要一个完整的开关盒用于数字 0 到 10。
在从 14 到 19 的每个数字名称后添加“teen”（例如：14：四个“teen”。）。
而不是为 20 到 99 范围内的数字添加“ty”和数字名称。
等等。
我认为必须有一些更好的方法来解决这个问题。
首选 C 代码。
问问题
113406 次
8 回答
15
#include<iostream>
using namespace std;
void expand(int);
int main()
{
int num;
cout<<"Enter a number : ";
cin>>num;
expand(num);
}
void expand(int value)
{
const char * const ones[20] = {"zero", "one", "two", "three","four","five","six","seven",
"eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen",
"eighteen","nineteen"};
const char * const tens[10] = {"", "ten", "twenty", "thirty","forty","fifty","sixty","seventy",
"eighty","ninety"};
if(value<0)
{
cout<<"minus ";
expand(-value);
}
else if(value>=1000)
{
expand(value/1000);
cout<<" thousand";
if(value % 1000)
{
if(value % 1000 < 100)
{
cout << " and";
}
cout << " " ;
expand(value % 1000);
}
}
else if(value >= 100)
{
expand(value / 100);
cout<<" hundred";
if(value % 100)
{
cout << " and ";
expand (value % 100);
}
}
else if(value >= 20)
{
cout << tens[value / 10];
if(value % 10)
{
cout << " ";
expand(value % 10);
}
}
else
{
cout<<ones[value];
}
return;
}
于 2012-11-27T08:20:12.710 回答
3
考虑使用由小值索引的字符串表，而不是 switch 语句。
const char * const ones[20] = {"zero", "one", "two", ..., "nineteen"};
const char * const tens[10] = {"", "ten", "twenty", ..., "ninety"};
现在把问题分解成小块。编写一个可以输出一位数的函数。然后编写一个可以处理两位数的函数（可能会使用前面的函数）。根据需要继续构建功能。
创建具有预期输出的测试用例列表，并编写代码来调用您的函数并检查输出，这样，当您为更复杂的用例解决问题时，您可以确保更简单的用例继续工作。
于 2012-09-05T17:07:55.293 回答
2
如果您对现成的解决方案感兴趣，那么您可以查看 HumanizerCpp 库 ( https://github.com/trodevel/HumanizerCpp ) - 它是 C# Humanizer 库的一个端口，它完全符合您的要求。
它甚至可以转换为序数，目前支持 3 种语言：英语、德语和俄语。
例子：
const INumberToWordsConverter * e = Configurator::GetNumberToWordsConverter( "en" );
std::cout << e->Convert( 123 ) << std::endl;
std::cout << e->Convert( 1234 ) << std::endl;
std::cout << e->Convert( 12345 ) << std::endl;
std::cout << e->Convert( 123456 ) << std::endl;
std::cout << std::endl;
std::cout << e->ConvertToOrdinal( 1001 ) << std::endl;
std::cout << e->ConvertToOrdinal( 1021 ) << std::endl;
const INumberToWordsConverter * g = Configurator::GetNumberToWordsConverter( "de" );
std::cout << std::endl;
std::cout << g->Convert( 123456 ) << std::endl;
const INumberToWordsConverter * r = Configurator::GetNumberToWordsConverter( "ru" );
std::cout << r->ConvertToOrdinal( 1112 ) << std::endl;
输出：
one hundred and twenty-three
one thousand two hundred and thirty-four
twelve thousand three hundred and forty-five
one hundred and twenty-three thousand four hundred and fifty-six
thousand and first
thousand and twenty-first
einhundertdreiundzwanzigtausendvierhundertsechsundfünfzig
одна тысяча сто двенадцатый
在任何情况下，您都可以查看源代码并在项目中重用或尝试理解逻辑。它是用纯 C++ 编写的，没有外部库。
问候， 塞尔吉
于 2015-08-27T07:12:21.323 回答
1
/* This Program will convert Numbers from -999,999,999 to 999,999,999 into words */
#include <vector>
#include <iostream>
#include <stdexcept>
#include <string>
using namespace std;
const std::vector<std::string> first14 = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen" };
const std::vector<std::string> prefixes = { "twen", "thir", "for", "fif", "six", "seven", "eigh", "nine" };
std::string inttostr(const int number)
{
if (number < 0)
{
return "minus " + inttostr(-number);
}
if (number <= 14)
return first14.at(number);
if (number < 20)
return prefixes.at(number - 12) + "teen";
if (number < 100) {
unsigned int remainder = number - (static_cast<int>(number / 10) * 10);
return prefixes.at(number / 10 - 2) + (0 != remainder ? "ty " + inttostr(remainder) : "ty");
}
if (number < 1000) {
unsigned int remainder = number - (static_cast<int>(number / 100) * 100);
return first14.at(number / 100) + (0 != remainder ? " hundred " + inttostr(remainder) : " hundred");
}
if (number < 1000000) {
unsigned int thousands = static_cast<int>(number / 1000);
unsigned int remainder = number - (thousands * 1000);
return inttostr(thousands) + (0 != remainder ? " thousand " + inttostr(remainder) : " thousand");
}
if (number < 1000000000) {
unsigned int millions = static_cast<int>(number / 1000000);
unsigned int remainder = number - (millions * 1000000);
return inttostr(millions) + (0 != remainder ? " million " + inttostr(remainder) : " million");
}
throw std::out_of_range("inttostr() value too large");
}
int main()
{
int num;
cout << "Enter a number to convert it into letters : ";
cin >> num;
cout << endl << num << " = " << inttostr(num) << endl;
system("pause");
return 0;
}
于 2014-12-04T11:05:50.573 回答
1
适用于从0到999999999 的任何数字。
这个程序从用户那里得到一个数字，把它分成三部分，然后分别存储在一个数组中。这三个数字通过将它们转换为单词的函数传递。然后它在第一部分加上“百万”，在第二部分加上“千”。
#include <iostream>
using namespace std;
int buffer = 0, partFunc[3] = {0, 0, 0}, part[3] = {0, 0, 0}, a, b, c, d;
long input, nFake = 0;
const char ones[][20] = {"", "one", "two", "three",
"four", "five", "six", "seven",
"eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"};
const char tens[][20] = {"", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"};
void convert(int funcVar);
int main() {
cout << "Enter the number:";
cin >> input;
nFake = input;
buffer = 0;
while (nFake) {
part[buffer] = nFake % 1000;
nFake /= 1000;
buffer++;
}
if (buffer == 0) {
cout << "Zero.";
} else if (buffer == 1) {
convert(part[0]);
} else if (buffer == 2) {
convert(part[1]);
cout << " thousand,";
convert(part[0]);
} else {
convert(part[2]);
cout << " million,";
if (part[1]) {
convert(part[1]);
cout << " thousand,";
} else {
cout << "";
}
convert(part[0]);
}
system("pause");
return (0);
}
void convert(int funcVar) {
buffer = 0;
if (funcVar >= 100) {
a = funcVar / 100;
b = funcVar % 100;
if (b)
cout << " " << ones[a] << " hundred and";
else
cout << " " << ones[a] << " hundred ";
if (b < 20)
cout << " " << ones[b];
else {
c = b / 10;
cout << " " << tens[c];
d = b % 10;
cout << " " << ones[d];
}
} else {
b = funcVar;
if (b < 20)
cout << ones[b];
else {
c = b / 10;
cout << tens[c];
d = b % 10;
cout << " " << ones[d];
}
}
}
于 2015-02-08T03:32:07.940 回答
0
#include<stdio.h>
#include<conio.h>
void main()
{
int len=0,revnum,i,dup=0,j=0,k=0;
long int gvalue;
char ones[] [10]={"one","Two","Three","Four","Five","Six","Seven","Eight","Nine","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen",""};
char twos[][10]={"Ten","Twenty","Thirty","Fourty","fifty","Sixty","Seventy","eighty","Ninety",""};
clrscr();
printf("\n Enter value");
scanf("%ld",&gvalue);
if(gvalue==10)
printf("Ten");
else if(gvalue==100)
printf("Hundred");
else if(gvalue==1000)
printf("Thousand");
dup=gvalue;
for(i=0;dup>0;i++)
{
revnum=revnum*10+dup%10;
len++;
dup=dup/10;
}
while(j<len)
{
if(gvalue<10)
{
printf("%s ",ones[gvalue-1]);
}
else if(gvalue>10&&gvalue<=19)
{
printf("%s ",ones[gvalue-2]);
break;
}
else if(gvalue>19&&gvalue<100)
{
k=gvalue/10;
gvalue=gvalue%10;
printf("%s ",twos[k-1]);
}
else if(gvalue>100&&gvalue<1000)
{
k=gvalue/100;
gvalue=gvalue%100;
printf("%s Hundred ",ones[k-1]);
}
else if(gvalue>=1000&&gvlaue<9999)
{
k=gvalue/1000;
gvalue=gvalue%1000;
printf("%s Thousand ",ones[k-1]);
}
else if(gvalue>=11000&&gvalue<=19000)
{
k=gvalue/1000;
gvalue=gvalue%1000;
printf("%s Thousand ",twos[k-2]);
}
else if(gvalue>=12000&&gvalue<100000)
{
k=gvalue/10000;
gvalue=gvalue%10000;
printf("%s ",ones[gvalue-1]);
}
else
{
printf("");
}
j++;
getch();
}
于 2013-09-14T06:00:21.147 回答
0
import java.lang.*;
import java.io.*;
public class rupee
{
public static void main(String[] args)throws IOException
{
int len=0,revnum=0,i,dup=0,j=0,k=0;
int gvalue;
String[] ones={"one","Two","Three","Four","Five","Six","Seven","Eight","Nine","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen",""};
String[] twos={"Ten","Twenty","Thirty","Fourty","fifty","Sixty","Seventy","eighty","Ninety",""};
System.out.println("\n Enter value");
InputStreamReader b=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(b);
gvalue=Integer.parseInt(br.readLine());
if(gvalue==10)
System.out.println("Ten");
else if(gvalue==100)
System.out.println("Hundred");
else if(gvalue==1000)
System.out.println("Thousand");
dup=gvalue;
for(i=0;dup>0;i++)
{
revnum=revnum*10+dup%10;
len++;
dup=dup/10;
}
while(j<len)
{
if(gvalue<10)
{
System.out.println(ones[gvalue-1]);
}
else if(gvalue>10&&gvalue<=19)
{
System.out.println(ones[gvalue-2]);
break;
}
else if(gvalue>19&&gvalue<100)
{
k=gvalue/10;
gvalue=gvalue%10;
System.out.println(twos[k-1]);
}
else if(gvalue>100&&gvalue<1000)
{
k=gvalue/100;
gvalue=gvalue%100;
System.out.println(ones[k-1] +"Hundred");
}
else if(gvalue>=1000&&gvalue<9999)
{
k=gvalue/1000;
gvalue=gvalue%1000;
System.out.println(ones[k-1]+"Thousand");
}
else if(gvalue>=11000&&gvalue<=19000)
{
k=gvalue/1000;
gvalue=gvalue%1000;
System.out.println(twos[k-2]+"Thousand");
}
else if(gvalue>=12000&&gvalue<100000)
{
k=gvalue/10000;
gvalue=gvalue%10000;
System.out.println(ones[gvalue-1]);
}
else
{
System.out.println("");
}
j++;
}
}
}
于 2013-09-14T06:43:27.957 回答
0
/*Maximum value that can be entered is 2,147,483,647
* Program to convert entered number into string
* */
import java.util.Scanner;
public class NumberToWords
{
public static void main(String[] args)
{
double num;//for taking input number
Scanner obj=new Scanner(System.in);
do
{
System.out.println("\n\nEnter the Number (Maximum value that can be entered is 2,147,483,647)");
num=obj.nextDouble();
if(num<=2147483647)//checking if entered number exceeds maximum integer value
{
int number=(int)num;//type casting double number to integer number
splitNumber(number);//calling splitNumber-it will split complete number in pairs of 3 digits
}
else
System.out.println("Enter smaller value");//asking user to enter a smaller value compared to 2,147,483,647
}while(num>2147483647);
}
//function to split complete number into pair of 3 digits each
public static void splitNumber(int number)
{ //splitNumber array-contains the numbers in pair of 3 digits
int splitNumber[]=new int[4],temp=number,i=0,index;
//splitting number into pair of 3
if(temp==0)
System.out.println("zero");
while(temp!=0)
{
splitNumber[i++]=temp%1000;
temp/=1000;
}
//passing each pair of 3 digits to another function
for(int j=i-1;j>-1;j--)
{ //toWords function will split pair of 3 digits to separate digits
if(splitNumber[j]!=0)
{toWords(splitNumber[j]);
if(j==3)//if the number contained more than 9 digits
System.out.print("billion,");
else if(j==2)//if the number contained more than 6 digits & less than 10 digits
System.out.print("million,");
else if(j==1)
System.out.print("thousand,");//if the number contained more than 3 digits & less than 7 digits
}
}
}
//function that splits number into individual digits
public static void toWords(int number)
//splitSmallNumber array contains individual digits of number passed to this function
{ int splitSmallNumber[]=new int[3],i=0,j;
int temp=number;//making temporary copy of the number
//logic to split number into its constituent digits
while(temp!=0)
{
splitSmallNumber[i++]=temp%10;
temp/=10;
}
//printing words for each digit
for(j=i-1;j>-1;j--)
//{ if the digit is greater than zero
if(splitSmallNumber[j]>=0)
//if the digit is at 3rd place or if digit is at (1st place with digit at 2nd place not equal to zero)
{ if(j==2||(j==0 && (splitSmallNumber[1]!=1)))
{
switch(splitSmallNumber[j])
{
case 1:System.out.print("one ");break;
case 2:System.out.print("two ");break;
case 3:System.out.print("three ");break;
case 4:System.out.print("four ");break;
case 5:System.out.print("five ");break;
case 6:System.out.print("six ");break;
case 7:System.out.print("seven ");break;
case 8:System.out.print("eight ");break;
case 9:System.out.print("nine ");break;
}
}
//if digit is at 2nd place
if(j==1)
{ //if digit at 2nd place is 0 or 1
if(((splitSmallNumber[j]==0)||(splitSmallNumber[j]==1))&& splitSmallNumber[2]!=0 )
System.out.print("hundred ");
switch(splitSmallNumber[1])
{ case 1://if digit at 2nd place is 1 example-213
switch(splitSmallNumber[0])
{
case 1:System.out.print("eleven ");break;
case 2:System.out.print("twelve ");break;
case 3:System.out.print("thirteen ");break;
case 4:System.out.print("fourteen ");break;
case 5:System.out.print("fifteen ");break;
case 6:System.out.print("sixteen ");break;
case 7:System.out.print("seventeen ");break;
case 8:System.out.print("eighteen ");break;
case 9:System.out.print("nineteen ");break;
case 0:System.out.print("ten ");break;
}break;
//if digit at 2nd place is not 1
case 2:System.out.print("twenty ");break;
case 3:System.out.print("thirty ");break;
case 4:System.out.print("forty ");break;
case 5:System.out.print("fifty ");break;
case 6:System.out.print("sixty ");break;
case 7:System.out.print("seventy ");break;
case 8:System.out.print("eighty ");break;
case 9:System.out.print("ninety ");break;
//case 0: System.out.println("hundred ");break;
}
}
}
}
}
于 2014-06-12T06:31:11.230 回答