2

我编写了这个IQueryable<T>按列排序的代码sortColumn。我想扩展它，以便将列值BirthDate等于的条目DateTime.Today放在排序的第一位，但我只是找不到或想不出如何完成这项工作。

public static IQueryable<T> OrderByField<T>(this IQueryable<T> q, string sortColumn, bool asc)
{
    var param = Expression.Parameter(typeof(T), "p");

    var prop = Expression.Property(param, sortColumn);

    var exp = Expression.Lambda(prop, param);

    string method = asc ? "OrderBy" : "OrderByDescending";

    Type[] types = new[] { q.ElementType, exp.Body.Type };

    var mce = Expression.Call(typeof(Queryable), method, types, q.Expression, exp);

    return q.Provider.CreateQuery<T>(mce);
}
4

2 回答 2

8

请参阅处理 GridView.OnSorting() 并使用 LINQ 动态创建排序表达式

public static class SortExpressionBuilder<T>
{
    private static IDictionary<SortDirection, ISortExpression> directions =  new Dictionary<SortDirection, ISortExpression>
    {
        { SortDirection.Ascending, new OrderByAscendingSortExpression() },
        { SortDirection.Descending, new OrderByDescendingSortExpression() }
    };

    interface ISortExpression
    {
        Func<IEnumerable<T>, Func<T, object>, IEnumerable<T>> GetExpression();
    }

    class OrderByAscendingSortExpression : ISortExpression
    {
        public Func<IEnumerable<T>, Func<T, object>, IEnumerable<T>> GetExpression()
        {
            return (c, f) => c.OrderBy(f);
        }
    }

    class OrderByDescendingSortExpression : ISortExpression
    {
        public Func<IEnumerable<T>, Func<T, object>, IEnumerable<T>> GetExpression()
        {
            return (c, f) => c.OrderByDescending(f);
        }
    }

    public static Func<IEnumerable<T>, Func<T, object>, IEnumerable<T>> CreateExpression(SortDirection direction)
    {
        return directions[direction].GetExpression();
    }
}

public static IEnumerable<T> OrderBy<T>(this IEnumerable<T> collection, string columnName, SortDirection direction)
{
    ParameterExpression param = Expression.Parameter(typeof(T), "x"); // x
    Expression property = Expression.Property(param, columnName);     // x.ColumnName
    Func<T, object> func = Expression.Lambda<Func<T, object>>(        // x => x.ColumnName
       Expression.Convert(Expression.Property(param, columnName), 
       typeof(object)), param
    ).Compile();

    Func<IEnumerable<T>, Func<T, object>, IEnumerable<T>> expression = SortExpressionBuilder<T>.CreateExpression(direction);
    IEnumerable<T> sorted = expression(collection, func);
    return sorted;
}

和底部的链接：

于 2012-09-07T17:12:17.953 回答
3

您可以尝试对类似于以下表达式的内容进行排序：

.OrderBy(x => BirthDate == DateTime.Now.Date ? 0 : 1).ThenBy(sortColumn);
于 2012-12-28T09:46:18.003 回答