1

我将数据从 SQL 加载到 CSV 文件。我的 csv 记录采用以下方式。 

Eid  ename  desig  sourceD  location  
1     Ralf   PM      1        UK  
1     Ralf   PM      1        USA  
2     Marty  PL      3         GBR  
3     Levis  BA      5        UK  
4     Ricky  BI      7        RSA  
4     Ricky  BI      7        FRA

现在我想将 EID 1 和 4 组合成单行。我的输出必须采用以下方式 

Eid  ename  desig  sourceD  location  
1     Ralf   PM      1        UK, USA  
2     Marty  PL      3         GBR  
3     Levis  BA      5        UK  
4     Ricky  BI      7        RSA, FRA

我只有 CSV 文件，我没有任何 sql 查询或任何东西。

4

1 回答 1

2

SQL小提琴

SQL 查询

    select c1.Eid, c1.ename,c1.desig,c1.sourceD,
    (   SELECT x.location + ', '
        FROM Contacts x
        WHERE c1.Eid = x.Eid
        ORDER BY x.location
        FOR XML PATH ('')
    ) as Locations
from Contacts c1
group by c1.Eid, c1.ename,c1.desig,c1.sourceD

在职的 ？

如果你想最后没有逗号：

    SELECT c1.Eid, c1.ename,c1.desig,c1.sourceD,
   LEFT( (   SELECT x.location + ', '
        FROM Contacts x
        WHERE c1.Eid = x.Eid
        ORDER BY x.location
        FOR XML PATH ('')
    ),LEN((   SELECT x.location + ', '
        FROM Contacts x
        WHERE c1.Eid = x.Eid
        ORDER BY x.location
        FOR XML PATH ('')
    ))-1) AS Locations
FROM Contacts c1
GROUP BY c1.Eid, c1.ename,c1.desig,c1.sourceD

此查询将使您避免长度为 0：

    SELECT c1.Eid, c1.ename,c1.desig,c1.sourceD,
   LEFT( (   SELECT x.location + ', '
        FROM Contacts x
        WHERE c1.Eid = x.Eid
        ORDER BY x.location
        FOR XML PATH ('')
    ),CASE WHEN LEN((   SELECT x.location + ', '
        FROM Contacts x
        WHERE c1.Eid = x.Eid
        ORDER BY x.location
        FOR XML PATH ('')
    ))=0 THEN 1 ELSE LEN((   SELECT x.location + ', '
        FROM Contacts x
        WHERE c1.Eid = x.Eid
        ORDER BY x.location
        FOR XML PATH ('')
    )) END -1) AS Locations
FROM Contacts c1
GROUP BY c1.Eid, c1.ename,c1.desig,c1.sourceD
于 2012-09-05T08:45:18.663 回答