1

到目前为止,我可以将图像上传到文件夹并将名称保存在数据库中。我想要做的是能够在浏览器中查看每个图像,并在其旁边或下方使用相应的名称。但我所拥有的是错误的图像分配了错误的名称。我浏览器中的第一张图片在数据库中的记录中被分配了接下来的两个名称。我究竟做错了什么?请我需要帮助。

这是我的代码:

添加页面:-

    <table width="760" border="0" align="center" cellpadding="0" cellspacing="0">
      <tr>
        <td height="100" align="center" bgcolor="#CC0000" class="header_title">Facilitators Panel
          <table width="600" height="30" border="0" cellspacing="0" cellpadding="0">
            <tr>
              <td width="448" class="header_title" height="20"></td>
              <td width="92" class="text2"><a href="cpanel.php?user=<?php echo $row_rsadmin['aID']; ?>">Control Panel</a></td>
              <td width="60" class="text2">Logout</td>
            </tr>
          </table></td>
      </tr>
      <tr>
        <td height="300" valign="top" bgcolor="#666666" class="text2"><table width="640" border="0" cellspacing="0" cellpadding="0">
          <tr>
            <td>&nbsp;</td>
          </tr>
          <tr>
            <td class="text2"><a href="adfacilitators.php?user=<?php echo $row_rsadmin['aID']; ?>">Back</a></td>
          </tr>
          <tr>
            <td class="text2">&nbsp;</td>
          </tr>
        </table>
          <table width="640" border="0" align="center" cellpadding="0" cellspacing="0">
          <tr>
            <td width="640" height="40" colspan="4" align="center"><form action="fac.php" method="post" enctype="multipart/form-data" name="fac" id="fac">
      <table width="580" border="0" cellpadding="0" cellspacing="0">
        <tr>
          <td height="1" align="right">&nbsp;</td>
        </tr>
        <tr>
          <td width="132" align="right" class="text3">Name:</td>
          <td width="10" rowspan="4">&nbsp;</td>
          <td colspan="2"><label>
            <input name="name" type="text" class="textbox" id="name" />
          </label></td>
        </tr>
        <tr>
          <td height="45" align="right"><p class="text3">Photo:</p></td>
          <td width="272" height="45"><input type="hidden" name="MAX_FILE_SIZE" value="256000" />
            <input name="photo" type="file" id="photo" size="26" /></td>
          <td width="166">&nbsp;</td>
        </tr>
        <tr>
          <td height="1" align="right">&nbsp;</td>
        </tr>
        <tr>
          <td height="40" align="right">&nbsp;</td>
          <td colspan="2" valign="top"><label>
            <input name="button" type="submit" class="readmore" id="button" value="Submit" />
          </label>
            <input name="button2" type="reset" class="readmore" id="button2" value="Reset" /></td>
        </tr>
      </table>
    </form></td>
          </tr>
          <tr>
            <td height="10" colspan="4" align="center"></td>
          </tr>
          </table></p></td></tr>
    </table>

处理页面:-

    <?php require("../Connections/connMain.php"); ?>
    <?php

                // validation... since this is an image upload script we should run a check   
                // to make sure the uploaded file is in fact an image. Here is a simple check: 
                // getimagesize() returns false if the file tested is not an image. 
                if ($image = @getimagesize($_FILES['photo']['tmp_name'])&& ($_FILES["photo"]["size"]<= 2560000))
                {}
                else
                {
                    header("Location:error1.php");

                exit;
                }


       //This gets all the other information from the form 
      $name = htmlspecialchars($_POST['name']);
      $pix= ($_FILES['photo']['name']);
      $tmpName = $_FILES['photo']['tmp_name']; 


     //Writes the information to the database 
     mysql_query("INSERT INTO facilitators (photo, name) VALUES ('$pix', '$name')"); 


     //This is the directory where images will be saved 
     // Make sure the file was sent without errors
     //if($_FILES['photo']['error'] == 0) {
     $target = "../facilitators/";

     $target = $target  . basename( $_FILES['photo']['name']); 


     //Writes the photo to the server 
     if(move_uploaded_file($tmpName, $target)) 
     { 

     header("Location:adfacilitators.php");

     }
     else { 

     header("Location:error2.php");

     }
    ?>

输出页面:

<div id="wrapper2">
    <div id="headercont"><?php require_once('header.html'); ?></div>
    <div id="bannercont"><?php require_once('banner.html'); ?></div>
    <div id="mainbody">
      <div id="sidelink"><?php require_once('sidelink.html'); ?></div>
        <div id="mainbodyr">
          <div class="clear_4"></div>
          <div id="subheadertext">Facilitators</div>
          <div class="clear_4"></div>
          <div id="mainbodycontentcont">
            <?php do { ?>
            <table width="520" border="0" cellspacing="0" cellpadding="0">
              <tr>
                <td width="150"><div id="mainbodypiccont">
                  <? $info = mysql_fetch_array( $rsFacilitator ); echo "<img src=http://localhost/youngatart/facilitators/".$info['photo'] ." width='150'>" ?>
                </div></td>
                <td width="370"><div id="mainbodytextcont">
                  <div id="text1"><?php echo $row_rsFacilitator['name']; ?></div>
                </div></td>
              </tr>
              <tr>
                <td height="20" colspan="2"></td>
              </tr>
            </table>
              <?php } while ($row_rsFacilitator = mysql_fetch_assoc($rsFacilitator)); ?>
          </div>
        </div>
        <div class="clear_5"></div>
    </div>
    </div>
</body>
4

2 回答 2

2

检查一下,我已经稍微更改了您的代码,

<div id="mainbodycontentcont">
            <?php while ($row_rsFacilitator = mysql_fetch_assoc($rsFacilitator) { ?>
            <table width="520" border="0" cellspacing="0" cellpadding="0">
              <tr>
                <td width="150"><div id="mainbodypiccont">
                  <? echo "<img src=http://localhost/youngatart/facilitators/".$row_rsFacilitator['photo'] ." width='150'>" ?>
                </div></td>
                <td width="370"><div id="mainbodytextcont">
                  <div id="text1"><?php echo $row_rsFacilitator['name']; ?></div>
                </div></td>
              </tr>
              <tr>
                <td height="20" colspan="2"></td>
              </tr>
            </table>
              <?php }?>
          </div>

编辑 我并不完全理解你的问题,但如果你想从图像中编辑你的数据,请点击给<a>图像添加标签。

<div id="mainbodycontentcont">
                <?php while ($row_rsFacilitator = mysql_fetch_assoc($rsFacilitator)) { ?>
                <table width="520" border="0" cellspacing="0" cellpadding="0">
                  <tr>
                    <td width="150"><div id="mainbodypiccont">
                      <? echo "<a href='yourfilename.php?imageid=1'><img src=http://localhost/youngatart/facilitators/".$row_rsFacilitator['photo'] ." width='150'></a>" ?>
                    </div></td>
                    <td width="370"><div id="mainbodytextcont">
                      <div id="text1"><a href='yourfilename.php?imageid=1'><?php echo $row_rsFacilitator['name']; ?></a></div>
                    </div></td>
                  </tr>
                  <tr>
                    <td height="20" colspan="2"></td>
                  </tr>
                </table>
                  <?php }?>
              </div>
于 2012-09-05T05:07:48.277 回答
1

很好看你的代码,你先插入了记录,然后你上传了文件。试着反过来做。首先上传文件。如果成功,将图片名称分配给变量$pix然后在数据库中插入东西。如果文件在目录中成功上传,则检查文件夹中是否存在。尝试将此文件的名称与刚插入数据库中的文件匹配。

此外,一点注意事项:

  • 避免使用不推荐使用mysql_的函数,使用mysqli_或 PDO。
  • 使用参数化查询。
于 2012-09-05T04:55:05.640 回答