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为什么我的 ajax 函数没有使用 get 方法提交两个值

<script language="javascript" type="text/javascript">
<!-- 
//Browser Support Code
function ajaxFunction( ){
    var ajaxRequest;  // The variable that makes Ajax possible!

    try{
        // Opera 8.0+, Firefox, Safari
        ajaxRequest = new XMLHttpRequest();
    } catch (e){
        // Internet Explorer Browsers
        try{
            ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            try{
                ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
            } catch (e){
                // Something went wrong
                alert("Your browser broke!");
                return false;
            }
        }
    }
    // Create a function that will receive data sent from the server
    ajaxRequest.onreadystatechange = function(){
        if(ajaxRequest.readyState == 4){
            document.getElementById("emailconfirm").innerHTML= ajaxRequest.responseText;
        }
    }

    ajaxRequest.open("GET", "Atest.php?<?php echo $PDFPassingArray ?>?Email="+ document.getElementById("email").value, true);
    ajaxRequest.send(null); 
}

我希望函数提交数组 $pdfpassingArray，这是一个 html_build_query 和表单中的电子邮件元素 id。目前我只能查看 $pdfPassingarray 值，但不能查看 Email 值。所以我的问题，我做这部分是否正确

ajaxRequest.open("GET", "Atest.php?<?php echo $PDFPassingArray ?>?Email="+ document.getElementById("email").value, true);

我的表格

       <form name='myForm'>

    <input name="email"   id="email"type="text" />
    <input name="button" onclick="ajaxFunction()" type="button" />
</form>
4

1 回答 1

3

您的 URL 字符串中有两个?s，

它应该是形式url.php?a=1&b=2

于 2012-09-04T19:53:00.360 回答